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MrMuchimi
2 years ago
10

There are 18 students on the debate club. How many ways can the club send 4 students to the next debate

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

There are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have the total number of students = 18

The number of ways the club send 4 students to the next debate is:

= C(18, 4)

= \rm \dfrac{18!}{4!(18-4)!}

= 3060

Thus, there are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

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18

Step-by-step explanation:

Factors of 54

1, 2, 3, 6, 9, 18, 27

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1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36

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1, 2, 3, 6, 9, 18.

Greatest Common Factor

We found the factors and prime factorization of 72, 54 and 18. The biggest common factor number is the GCF number.

So the greatest common factor 72, 54 and 18 is 18.

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Frank, mary and seth shared some sweets in the ratio 4;5;7
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