There are 18 students on the debate club. How many ways can the club send 4 students to the next debate
1 answer:
There are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.
<h3>What is permutation and combination?</h3>A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
We have the total number of students = 18
The number of ways the club send 4 students to the next debate is:
= C(18, 4)
= 3060
Thus, there are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.
Learn more about permutation and combination here:
#SPJ1
You might be interested in
Answer:
s =
Step-by-step explanation:
Given
v² = u² + 2as ( subtract u² from both sides )
v² - u² = 2as ( divide both sides by 2a )
= s
Given
v² = u² + 2as ( subtract 2as from both sides )
v² - 2as = u² ( take the square root of both sides )
± = u