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MrMuchimi
2 years ago
10

There are 18 students on the debate club. How many ways can the club send 4 students to the next debate

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

There are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have the total number of students = 18

The number of ways the club send 4 students to the next debate is:

= C(18, 4)

= \rm \dfrac{18!}{4!(18-4)!}

= 3060

Thus, there are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

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Due to a formula limit, I cannot apply the visual product here but I assume you can easily do this part! I believe I will be switching over to paint.net to provide pictures of work for long division!

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{18}{867}\:\mathrm{is}\:0\:\mathrm{with\:a\;remainder\:of}\:18

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