1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
posledela
4 years ago
12

A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain al

titude is: Convert to .
Physics
1 answer:
Vlada [557]4 years ago
5 0

Answer:

= 4.21\times 10^{-10}J/cm^4

Explanation:

According to the given situation, the computation is shown below:-

1kPa=10^3Pa

So,

1Km = 10^5cm

1kPa=0.01Pa/Cm

1kPa=10^{-8}J/cm^4

Now as per the question it is given that

r = 0.0421KPa/Km

= 0.0421KPa/Km \times \frac{10^{-8}J/cm^4}{1KPa/Km}

after solving the above equation we will get

= 0.0421\times 10^{-8}J/cm^4

or we can write the above equation in this manner, that is

= 4.21\times 10^{-10}J/cm^4

Therefore we have solved the equation to reach the right answer.

You might be interested in
When and where was the worst hurricane in the united states
Andre45 [30]
It was in Texas on September 8, 1900.
8 0
3 years ago
Finding the spring constant as shown, spring 3, which has an unknown spring constant k3, replaces spring 2. the mass of the weig
nevsk [136]
Replaces spring 2. the mass of the weight and pulley are unchanged: m=5.8 kg and mp=1.7 kg
6 0
4 years ago
If mass is the amount of MATTER present in the
Korvikt [17]

Answer:

Yes it would be different on Earth and the moon

6 0
3 years ago
Read 2 more answers
As part of a daring rescue attempt, the Millennium Eagle coasts between a pair of twin asteroids, as shown in the figure below w
Luden [163]
The correct answer is 3 wiv 2=6
4 0
3 years ago
In a particular case of an object in front of a spherical mirror with a focal length of +12.0 cm, the magnification is +4.00.(a)
salantis [7]

Answer:

9 cm

-36 cm

Explanation:

u = Object distance

v = Image distance

f = Focal length = 12

m = Magnification = 4

m=-\frac{v}{u}\\\Rightarrow 4=-\frac{v}{u}\\\Rightarrow v=-4u

Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{12}=\frac{1}{u}+\frac{1}{-4u}\\\Rightarrow \frac{1}{12}=\frac{3}{4u}\\\Rightarrow u=9\ cm

Object distance is 9 cm

v=-4\times 9=-36\ cm

Image distance is -36 cm (other side of object)

7 0
3 years ago
Other questions:
  • For which job would a noise canceling device be the most beneficial?
    15·2 answers
  • How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it
    14·1 answer
  • The 16.0-in. spring is compressed to a 9.9-in. length, where it is released from rest and accelerates the sliding block A. The a
    12·1 answer
  • HELP ASAPP!!!! MARKING BRAINLIEST!
    15·2 answers
  • Grinding quartz crystals down to produce sand is an example of a a. change of state. c. chemical reaction. b. chemical change. d
    7·1 answer
  • Allison wants to determine the density of a bouncing ball. which metric measurements must she use?
    10·1 answer
  • Is the hand grip test an example of an isometric or an isotonic muscle contraction? Explain your reasoning.
    7·1 answer
  • TheStability of atomic nuclei seems to be related to the ratio of what
    9·1 answer
  • 4.
    6·1 answer
  • Which of the following statements is true vibrations ?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!