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3 years ago

The pulse site located at the point where the upper leg bends is called the

1 answer:

3 0

The pulse site located at the point where the upper leg bends is called the femoral. It is an artery found in the thigh. It is large and is deemed as the main arterial supply for the lower part of the body. It is known as the second artery that is the largest. It is being used as the catheter access artery. From it, diagnostics for the heart, brain, arms, kidney and other parts can be directed to the other arterial system. It can also be used as a source to draw blood that is from the arteries when there is low blood pressure.

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Two students, Jenny and Cho, are investigating motion.

IgorLugansk [536]

Answer:

1: a measuring instruments the students should use for time is a stopwatch

2: a measuring instruments the students should use for distance is a measuring tape

Explanation:

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1 year ago

What does the speed of sound depend on?

mr Goodwill [35]

I believe it's 'A'. Hopefully this helps!~ :)

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3 years ago

Read 2 more answers

A cat leaps into the air to catch a bird with an initial speed of 2.74 m/s at an angle of 60.0° above the ground. What is the hi

Volgvan

Answer: D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

$y=V_{o}sin\theta t-\frac{gt^{2}}{2}$ (1)

$V_{y}=V_{oy}-gt$ (2)

Where:

$y$ is the height of the cat

$V_{oy}=V_{o}sin\theta$ is the cat's initial velocity

$\theta=60\°$

$g=9.8m/s^{2}$ is the acceleration due gravity

$t$ is the time

$V_{y}$ is the y-component of the velocity

Now the cat will have its maximum height $y_{max}$ when $V_{y}=0$ . So equation (2) is rewritten as:

$0=V_{oy}-gt$ (3)

Finding $t$ :

$t=\frac{V_{oy}}{g}=\frac{V_{o}sin\theta}{g}$ (4)

$t=\frac{2.74 m/s sin(60\°)}{9.8m/s^{2}}$ (5)

$t=0.24 s$ (6)

Substituting (6) in (1):

$y_{max}=(2.74 m/s)sin(60\°) (0.24 s)-\frac{(9.8m/s^{2})(0.24 s)^{2}}{2}$ (7)

Finally:

$y_{max}=0.287 m \approx 0.29 m$ (8)

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3 years ago

A rectangular beam 10 cm wide, is subjected to a maximum shear force of 50000 N, the corresponding maximum shear stress being 3

nika2105 [10]

Answer:

Option B is the correct answer.

Explanation:

Shear stress is the ratio of shear force to area.

We have

Shear stress = 3 N/mm² = 3 x 10⁶ N/m²

Area = Area of rectangle = 10 x 10⁻² x d = 0.1d

Shear force = 50000 N

Substituting

$\texttt{Shear stress}=\frac{\texttt{Shear force}}{\texttt{Area}}\\\\3\times 10^6=\frac{50000}{0.1d}\\\\d=0.1667m=16.67cm$

Width of beam = 16.67 cm

Option B is the correct answer.

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3 years ago

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3 years ago