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chubhunter [2.5K]

3 years ago

12

An electron with a charge value of 1.6 x 10-19 C is moving in the presence of an electric field of 400 N/C. What force does the

electron experience?

1 answer:

Vsevolod [243]3 years ago

4 0

Answer:

4.0×10⁻¹⁷ N

Explanation:

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An elementary particle of mass m completely absorbs a photon, after which its mass is 1.01m. (a) what was the energy of the inco

sdas [7]

A.) We use the famous equation proposed by Albert Einstein written below:

E = Δmc²
where
E is the energy of the photon
Δm is the mass defect, or the difference of the mass before and after the reaction
c is the speed of light equal to 3×10⁸ m/s

Substituting the value:

E = (1.01m - m)*(3×10⁸ m/s) = 0.01mc² = 3×10⁶ Joules

b) The actual energy may be even greater than 3×10⁶ Joules because some of the energy may have been dissipated. Not all of the energy will be absorbed by the photon. Some energy would be dissipated to the surroundings.

8 0

3 years ago

How do I do this?<br> Series and parallel circuits.

Svetlanka [38]

Connect the little light thingys to the top of the battery

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3 years ago

A lamp has a current of 2.17 A. In hours, how long does it take for 1 mole of electrons to pass through the lamp?

Gennadij [26K]

<u>Answer:</u> The amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

<u>Explanation:</u>

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=9.6352\times 10^4C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 2.17 A

q = total charge = $9.6352\times 10^4C$

t = time required = ?

Putting values in above equation, we get:

$2.17A=\frac{9.6352\times 10^4C}{t}\\\\t=\frac{9.6352\times 10^4C}{2.17A}=44402s$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $44402s\times \frac{1hr}{3600s}=12.33hr$

Hence, the amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

3 0

3 years ago

The resistance of a light bulb that draws a current of 2 a when connected t a 12 v battery is?

8090 [49]

Explanation:

$V = I *R$

where:

V is the voltage

I is the current

R is the resistance

Rearranging, we have:

$R = \frac{V}{I} = \frac{12}{2}$ = ?

7 0

4 years ago

If the radius of the equipotential surface of the point charge is 14.3 m at a potential of 2.20 kV, what will be the magnitude o

PSYCHO15rus [73]

Answer:

The magnitude of the point charge is 3.496 x 10⁻⁶ C

Explanation:

Given;

radius of the surface, r = 14.3 m

magnitude of the potential, V = 2.2 kV = 2,200 V

The magnitude of the point charge is calculated as follows;

$V = (\frac{1}{4\pi \epsilon _0} )(\frac{Q}{r} )\\\\V = \frac{KQ}{r} \\\\Q = \frac{Vr}{K} \\\\Q = \frac{2,200 \times 14.3}{9\times 10^9} \\\\Q = 3.496 \times 10^{-6} \ C\\\\Q = 3.496 \ \mu C$

Therefore, the magnitude of the point charge is 3.496 μC

6 0

3 years ago