1. The mass of NaCl needed to react with F₂ at 280 K and 1.50 atm is 91.26 g
2. The mass of NaCl needed to react with F₂ at STP is 63.18 g
<h3>1. How to determine mass of NaCl needed at 280 K and 1.50 atm</h3>
First, we shall determine number of mole of F₂ by using the ideal gas equation as follow:
- Volume (V) = 12 L
- Temperature (T) = 280 K
- Pressure (P) = 1.5 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
- Number of mole (n) =?
n = PV / RT
n = (1.5 × 12) / (0.082 × 280)
n = 0.78 mole
Next, we shall determine the number of mole of NaCl that reacts. This is given below
F₂ + 2NaCl → Cl₂ + 2NaF
From the balanced equation above,
1 mole of F₂ reacted with 2 moles of NaCl.
Therefore,
0.78 mole of F₂ will react with = 0.78 × 2 = 1.56 mole of NaCl
Finally, we shall determine mass of NaCl as follow
- Mole of NaCl = 1.56 moles
- Molar mass of NaCl = 58.5 g/mol
- Mass of NaCl =?
Mass = mole × molar mass
Mass of NaCl = 1.56 × 58.5
Mass of NaCl = 91.26 g
<h3>2. How to determine mass of NaCl needed at STP</h3>
At standard temperature and pressure (STP),
22.4 L = 1 mole of F₂
Therefore,
12 L = 12 / 22.4
12 L = 0.54 mole of F₂
Next, we shall determine the number of mole NaCl that reacts. This is given below
F₂ + 2NaCl → Cl₂ + 2NaF
From the balanced equation above,
1 mole of F₂ reacted with 2 moles of NaCl.
Therefore,
0.54 mole of F₂ will react with = 0.54 × 2 = 1.08 mole of NaCl
Finally, we shall determine mass of NaCl as follow
- Mole of NaCl = 1.08 moles
- Molar mass of NaCl = 58.5 g/mol
- Mass of NaCl =?
Mass = mole × molar mass
Mass of NaCl = 1.08 × 58.5
Mass of NaCl = 63.18 g
Learn more about ideal gas equation:
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