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ololo11 [35]
3 years ago
12

As a distant star moves away from earth, the light given off by the star has a

Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

The wavelength of these photons will become longer. The energy of each of these photons will become lower.

Explanation:

<h3>Wavelength</h3>

Light can be considered as electromagnetic waves. The wavelength of a wave is equal to the minimum distance between two troughs (lowest points) in this wave. On the other hand, the frequency of a wave is equal to the number of wavelengths that this wave travels in unit time.

Assume that the speed of light stays the same. The distance that this beam of light travels in unit time will be the same. However, with a lower frequency, there would be fewer wavelengths in that same distance. Therefore, the size of each wavelength will become longer.

If c represent the speed of light and f represents the frequency, then the wavelength would be:

\displaystyle \lambda = \frac{c}{f}.

<h3>Energy</h3>

The energy E of each proton of a beam of light is proportional to the frequency f of the light. Let h denote Planck's Constant. The numerical relation between E\! and f\! would be:

E = h\, f.

Therefore, if the frequency f of this light becomes smaller, the energy E of each of its proton will also become proportionally lower.

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3 years ago
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the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th
Rainbow [258]
Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa

Have a nice day!
5 0
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