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ololo11 [35]
3 years ago
12

As a distant star moves away from earth, the light given off by the star has a

Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

The wavelength of these photons will become longer. The energy of each of these photons will become lower.

Explanation:

<h3>Wavelength</h3>

Light can be considered as electromagnetic waves. The wavelength of a wave is equal to the minimum distance between two troughs (lowest points) in this wave. On the other hand, the frequency of a wave is equal to the number of wavelengths that this wave travels in unit time.

Assume that the speed of light stays the same. The distance that this beam of light travels in unit time will be the same. However, with a lower frequency, there would be fewer wavelengths in that same distance. Therefore, the size of each wavelength will become longer.

If c represent the speed of light and f represents the frequency, then the wavelength would be:

\displaystyle \lambda = \frac{c}{f}.

<h3>Energy</h3>

The energy E of each proton of a beam of light is proportional to the frequency f of the light. Let h denote Planck's Constant. The numerical relation between E\! and f\! would be:

E = h\, f.

Therefore, if the frequency f of this light becomes smaller, the energy E of each of its proton will also become proportionally lower.

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Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

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B. gas state at room temperature

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The two observations we made from viewing the solar system model are as follows as:

1). When we look at the sky we observe that the motions of all the planets and the stars are perfect circular movements with a good and high speed, but not in velocity because in velocity direction doesn't charges.

2). The sun is at the centre of our solar system and all the planets are equidistant to each other planets and also revolve around the sun.

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