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ololo11 [35]
3 years ago
12

As a distant star moves away from earth, the light given off by the star has a

Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

The wavelength of these photons will become longer. The energy of each of these photons will become lower.

Explanation:

<h3>Wavelength</h3>

Light can be considered as electromagnetic waves. The wavelength of a wave is equal to the minimum distance between two troughs (lowest points) in this wave. On the other hand, the frequency of a wave is equal to the number of wavelengths that this wave travels in unit time.

Assume that the speed of light stays the same. The distance that this beam of light travels in unit time will be the same. However, with a lower frequency, there would be fewer wavelengths in that same distance. Therefore, the size of each wavelength will become longer.

If c represent the speed of light and f represents the frequency, then the wavelength would be:

\displaystyle \lambda = \frac{c}{f}.

<h3>Energy</h3>

The energy E of each proton of a beam of light is proportional to the frequency f of the light. Let h denote Planck's Constant. The numerical relation between E\! and f\! would be:

E = h\, f.

Therefore, if the frequency f of this light becomes smaller, the energy E of each of its proton will also become proportionally lower.

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The answer would be "false" or the second option. A opinion is what you think on a certain subject and science is full of facts and opinions of other scientist which would mean your using someone else for your opinion just remember opinions is what you think about a subject and you can't use science for your opinion.

Hope this helps!

7 0
3 years ago
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Which of the following is an example of an action done to maintain homeostasis?
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Ribosomes hope this helps if not oh well
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3 years ago
A radioisotope decays to give an alpha particle andPb-208.
oee [108]

<u>Answer:</u> The original element is _{84}^{212}\textrm{Po}

<u>Explanation:</u>

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

For the given alpha decay process of an isotope:

^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

A = 208 + 4

A = 212

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is _{84}^{212}\textrm{Po}

Hence, the original element is _{84}^{212}\textrm{Po}

3 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

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Name the planet: Until recently, this stormy, blue-colored planet had a great dark spot on it, which was a high pressure cyclone
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It’s Neptune hehe :))
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