calculate the volume of carbon dioxide of room temperature and pressure obtained from 30 grams of glucose
1 answer:
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Answer: 67.2 moles
Explanation:
According to the given balanced equation, 2 moles of acetylene combine with 5 moles of oxygen
to produce 4 moles of carbon dioxide
.
Thus if 2 moles of acetylene combine with = 5 moles of oxygen
35 moles of acetylene combine with=
moles of oxygen
But as only 84 moles of oxygen are available, acetylene is not a limiting reagent.
5 moles of oxygen reacts with = 2 moles of acetylene
84 moles of oxygen reacts with=
moles of acetylene
Thus Oxygen is the limiting reagent as it limits the formation of products. Acetylene is excess reagent as it is present in excess.
2 moles of acetylene produce= 4 moles of carbon dioxide
.
33.6 moles of acetylene produce=
moles of of carbon dioxide
.
Answer:
Activation energy of phenylalanine-proline peptide is 66 kJ/mol.
Explanation:
According to Arrhenius equation- , where k is rate constant, A is pre-exponential factor,
is activation energy, R is gas constant and T is temperature in kelvin scale.
As A is identical for both peptide therefore-
Here , T = 298 K , R = 8.314 J/(mol.K) and
So,
(rounded off to two significant digit)
So, activation energy of phenylalanine-proline peptide is 66 kJ/mol
Answer:
a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔGo and ΔG have the same magnitude, they just have opposite signs.
Explanation:
The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by . It is observed that the values of
changes with experimental conditions such as temperature , pressure , concentration etc.
is the standard free energy change which is a balance of two natural tendencies of any system.
- Minimization of potential energy or enthalpic factor
Maximization of disorderliness or entropic factor
Mathematically; =
-
Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:
ΔG⁰ and ΔG can have different values, they don't even have to have the same sign
For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point
If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.
while the false statements include:
a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.