All categories

2 years ago

I need help please!!

Mathematics

1 answer:

vivado [14]2 years ago

4 0

Answer:

Step-by-step explanation:

15 .12.9the sum of 5 4.3

You might be interested in

A stock that was purchased for $16.00 is now worth $96.<br> PLEASE HELP I MAY GIVE YOU A BRAINLIEST

Alchen [17]

Answer:

the stock would have a 600% increase of value

Step-by-step explanation:

im not sure if this is the answer you wanted but it would be 96/16

5 0

3 years ago

Read 2 more answers

Describe how to determine if two polygons have the same size and shape.

QveST [7]

You can identify similar polygon by comparing their corresponding angles and sides. ( if they are the same the ratio of the lengths is the scale factor. Also check if their sides are proportional.)

4 0

3 years ago

Read 2 more answers

3,000 kilometers with three friends 6 liters of gas per 100 kilometers and gas costs 1.20 per liter

dimaraw [331]

3000:100×6=180 liters
180×1,2=216 $
216÷6=36$/friend

4 0

3 years ago

Susan runs 22 km in 2 hours and 45 minutes. What is her average speed in km an hour?

12345 [234]

Answer:

4.97097

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago