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Olegator [25]
2 years ago
13

A rock is dropped from a bridge to the water below. It takes 2.40 s for the rock to hit the water (a) find the speed in m/s of t

he rock as it hits the water. (b) how high in metres is the bridge above the water
Physics
1 answer:
Artyom0805 [142]2 years ago
6 0

Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground

Explanation: Supposing that where not counting air resistance in the equation, the equation D = ut+\frac{1}{2}  at^{2} states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.

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A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is
Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

<u>brainly.com/question/13834772</u>

#SPJ4

7 0
2 years ago
A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.
34kurt
Given: Mass m = 60 Kg

           Weight  W = 96 N

Required: Acceleration due to gravity, g = ?

Formula:  W = mg

                g = W/g

                g = 96 Kg.m/s²/60 Kg   (note: this is the derive unit for Newton "N")

                g = 1.6 m/s²

6 0
3 years ago
Read 2 more answers
A=(v – u)/t<br><br> i. V as subject<br> ii. U as subject<br> iii. T as subject
Norma-Jean [14]

Answer:

i.

a =  \frac{(v - u)}{t}  \\ v - u = at \\ v = at + u

ii.

a =  \frac{(v - u)}{t}  \\ v - u = at \\ u = v - at

iii.

a =  \frac{(v - u)}{t}  \\ ta = v - u \\ t  =   \frac{(v - u)}{a}

I hope I helped you^_^

8 0
3 years ago
At the bottom of the ocean, a rock has a mass 25 g. At sea level, the same rock will have a mass of: less than 25 g, more than 2
storchak [24]
It will be same 25 g
5 0
4 years ago
Read 2 more answers
How long can a flashlight run for if it draws 0.11 amps and its battery contains 10 coulombs of change?
Alex17521 [72]

Answer:

Battery will run for t = 90 s

Explanation:

As we know that rate of flow of charge is known as electric current

So we will have

i = \frac{Q}{t}

i = 0.11 A

Q = 10 C

now we have

t = \frac{Q}{i}

t = \frac{10}{0.11}

t = 90 s

8 0
3 years ago
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