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2 years ago

An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?

Physics

1 answer:

Eduardwww [97]2 years ago

3 0

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical energy.

The formula of kinetic energy is given as;

Kinetic energy = $\frac{1}{2}$ m v²

where m is the mass, V is the velocity

substitute the parameters in the equation;

600 = $\frac{1}{2}$ x m x 15²

225m = 1200

m = $\frac{1200}{225}$ = 5.33kg

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2 years ago

A thin spherical spherical shell of radius R which carried a uniform surface charge density σ. Write an expression for the volum

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Answer:

Explanation:

From the given information:

We know that the thin spherical shell is on a uniform surface which implies that both the inside and outside the charge of the sphere are equal, Then

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∴

$\rho (r) \ \alpha \ \delta (r -R)$

$\rho (r) = k \ \delta (r -R) \ \ at \ \ (r = R)$

$\rho (r) = 0\ \ since \ r< R \ \ or \ \ r>R---- (1)$

To find the constant k, we examine the total charge Q which is:

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$\int^{2 \pi}_{0} d \phi* \int ^{\pi}_{0} \ sin \theta d \theta * \int ^{R}_{0} k \delta (r -R) * r^2dr = \sigma \times 4 \pi R^2$

$(2 \pi)(2) * \int ^{R}_{0} k \delta (r -R) * r^2dr = \sigma \times 4 \pi R^2$

Thus;

$k * 4 \pi \int ^{R}_{0} \delta (r -R) * r^2dr = \sigma \times R^2$

$k * \int ^{R}_{0} \delta (r -R) r^2dr = \sigma \times R^2$

$k * R^2= \sigma \times R^2$

$k = R^2 --- (2)$

Hence, from equation (1), if k = $\sigma$

$\mathbf{\rho (r) = \delta* \delta (r -R) \ \ at \ \ (r=R)}$

$\mathbf{\rho (r) =0 \ \ at \ \ rR}$

To verify the units:

$\mathbf{\rho (r) =\sigma \ * \ \delta (r-R)}$

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c/m³ c/m³ × 1/m

Thus, the units are verified.

The integrated charge Q

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$Q = (2 \pi) (2) \int ^R_0 \sigma * \delta (r-R) r^2 \ dr$

$Q = 4 \pi \sigma \int ^R_0 * \delta (r-R) r^2 \ dr$

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$\mathbf{Q = 4 \pi R^2 \sigma }$

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Answer:

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2 years ago

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Answer:

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3 years ago

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