Answer:
Explanation:
Therefore, the unit of speed is the meter per second, or m/s. The unit meter per second is called a derived unit, meaning that it is derived from the seven SI base units.
Explanation:
In the given question, the two metal spheres were hanged with the nylon thread.
When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.
The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.
During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.
It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.
Adding an intermediate switch is not an attractive choice to span the distance between two switches due to expense issues. It may have different ports.
<h3>What is a network switch?</h3>
A switch refers to a hardware tool capable of connecting different computer devices in a network.
A network switch can connect devices on a network by centralizing communications among many devices in a given local area network.
A switch may support different speeds for transmission of data (for example, one gigabit Gbps per second).
Learn more about network switches here:
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For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
<h3>What is the e
lectric field intensity 20cm away from the
rod along its perpendicular
bisector?</h3>
Generally, the equation for the initial electric field intensity is mathematically given as
Therefore
Hence
E1=B*9*10^{13})/(10*110)*
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
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