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wlad13 [49]
1 year ago
11

A ball is thrown straight up into the air and passes a window 3 seconds after being released. It passes the same window on its w

ay back down 1.5 seconds later. What was the initial velocity of the ball?
Physics
1 answer:
melomori [17]1 year ago
8 0

The  initial velocity of the ball is 55.125 m/s.

<h3>Initial velocity of the ball</h3>

The initial velocity of the ball is calculated as follows;

During upward motion

h = vi - ¹/₂gt²

h = vi - 0.5(9.8)(3²)

h = vi - 44.1 ----------------- (1)

During downward motion

h = vi + ¹/₂gt²

h = 0 + 0.5(9.8)(1.5)²

h = 11.025 ----------- (2)

solve (1) and (2) together, to determine the initial velocity of the ball

11.025 = vi - 44.1

vi = 11.025 + 44.1

vi = 55.125 m/s

Thus, the  initial velocity of the ball is 55.125 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

#SPJ1

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Explanation:

Given

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velocity of automobile v=10\ m/s

If the automobile crashes into the brick wall then it's kinetic energy is converted into thermal and demolishing energy to wall.

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E=\frac{1}{2}mv^2

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Find the value of F1 + F2 + F3.<br>​
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F = 0.78[N]

Explanation:

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Now we can sum each one of the forces in the given axes:

F_{x}=1-0.866=0.134[N]\\F_{y}=2-1.73+0.5\\F_{y}=0.77[N]

Now using the Pythagorean theorem we can find the total force.

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