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soldier1979 [14.2K]
3 years ago
8

F(x)= x^7+x^6+2x^5+8x^4+2x^3-3 what’s the intervals of inxreasing and decreasing

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer: please help me with this, I will do whatever you want but please help me please!

Step-by-step explanation:

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Please Find the solution to the following system using substitution or elimination: y = 3x + 7 y = -2x -3
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Answer: A (-2, 1)
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Some one factor 3x^2+7x-20
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3x^2+12x-5x-20
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F = 2x + y<br> 3x + 5y = 45 x20 and y20<br> 2x + 4&lt;32
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a

Step-by-step explanation:

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3 years ago
A typical television newscast has three cameras. The center camera directly faces the news anchors desk. The other two cameras a
Mnenie [13.5K]
<span>150 degrees. Let's assume the center camera is pointed to at an angle of 0 degrees. Since it has a coverage of 60 degrees, then it will cover the angles from -30 to +30 degrees. Now we'll continue to use the +/- 30 degree coverage for the other two cameras. The second camera is aimed at 45 degrees, so it's range of coverage is 15 degrees to 75 degrees (45 +/- 30). Notice that the range from 15 degrees to 30 degrees is covered by 2 cameras. Now the 3rd camera is pointed at -45 degrees, so its coverage is from -15 degrees to -75 degrees. It also has an overlap with the 1st camera from -15 to -30 degrees. The total coverage of all three cameras ranges from -75 degrees to 75 degrees. That means that an arc of 150 degrees in total is covered by all three cameras.</span>
7 0
3 years ago
What is 403,000,000,000,000 in scientific
frozen [14]

Answer:

(A) 4.03 x 10^14

Step-by-step explanation:

403,000,000,000,000

Scientific notation is of the form

a * 10 ^b

where a is a number from 1 to a number less than 10

Put the decimal in the number

403,000,000,000,000.

We need to move the decimal 14 places to the left to get the number to be between 1 and 10

4.03000000000000  so the b is 14

Since we moved it to the left b is positive

We can drop the extra zeros at the end (after the last nonzero digit)

4.03 *10^14

6 0
3 years ago
Read 2 more answers
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