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3 years ago

F(x)= x^7+x^6+2x^5+8x^4+2x^3-3 what’s the intervals of inxreasing and decreasing

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

Answer: please help me with this, I will do whatever you want but please help me please!

Step-by-step explanation:

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The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 15 minute

madam [21]

Answer:

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 3 minutes and 15 minutes:

So $a = 3, b = 15$

What is the probability that it takes Isabella more than 11 minutes to wait for the bus?

Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So

$P(X \leq 11) + P(X > 11) = 1$

We want P(X > 11). So

$P(X > 11) = 1 - P(X \leq 11) = 1 - \frac{11 - 3}{15 - 3} = 0.3333$

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

4 0

3 years ago

!MAGOR HELP! Question and answers are in the pic

Simora [160]

The first one is correct (-2/3, -1/2, 7/12, 0.82) pls mark branliest

8 0

3 years ago

Read 2 more answers

The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h

DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

Let X = lifetime of a battery in a certain application

So, X ~ N( $\mu=16,\sigma^{2} =2^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{ X -\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean lifetime = 16 hours

$\sigma$ = standard deviation = 2 hours

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

P(X > 19) = P( $\frac{ X -\mu}{\sigma}$ > $\frac{19-16}{2}$ ) = P(Z > 1.50) = 1 - P(Z $\leq$ 1.50)

= 1 - 0.9332 = 0.0668

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.

Hence, the probability that a battery will last more than 19 hours is 0.0668.

5 0

3 years ago

Please help with this, thanks

Readme [11.4K]

Answer:

BDC is half of mBC = 11°

Easily you see that C is A + BDC = 23°

Since C = 23° so mDC is twice = 46°