So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;
2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5
Hope this helps you. Any questions please ask.
Answer:
#1 - All real numbers are solutions.
#2 - All real numbers are solutions.
Step-by-step explanation:
#1 -
Let's solve your equation step-by-step.
12(6t−4)=3t−2
Step 1: Simplify both sides of the equation.
12(6t−4)=3t−2
(12)(6t)+(12)(−4)=3t+−2(Distribute)
3t+−2=3t+−2
3t−2=3t−2
Step 2: Subtract 3t from both sides.
3t−2−3t=3t−2−3t
−2=−2
Step 3: Add 2 to both sides.
−2+2=−2+2
0=0
Same for #2
Hello from MrBillDoesMath!
Answer: 104x^2 + 166x + 66
Discussion:
The area of a rectangle is given by "length" * "width". For us the formula becomes
(13x + 11) * (8x+6)
or
13x (8x +6) + 11 * (8x + 6) =
(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =
(104x^2 + 78x ) + (88x + 66) =
104x^2 + (78x + 88x) + 66 =
104x^2 + 166x + 66
Thank you,
MrB
Answer: c) 0.531441 = 0.53
e) 3.375 = 3.38 or 3.4
f)0.0289 =0.03
Step-by-step explanation: everyone will say that they will mark as brainliest but nobody does, you guys lie, but I still give the answers
