We know that
case a)the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.
Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1
Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1
the answer isa=1/9case b)the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h,
where (h, k) is the vertex.
Using our vertex, we have:
x=a(y+1)²+2,
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2
the answer isa=3
see the attached figure
900=(1/2)*b*10*15
1800=150b
b=12
I hope you can figure out FC with this info.
<span>arc length = circumference • [central angle (degrees) ÷ 360]
Solving this equation for circumference:
</span>
<span>circumference = arc length / (central angle / 360)
</span><span>circumference = 12 / (85/360)
</span>circumference = 12 / <span><span>0.2361111111
</span>
</span>
<span>circumference =
</span>
<span>
<span>
<span>
50.8235294118
</span>
</span>
</span>
Source:
http://www.1728.org/radians.htm
Answer:
OPTION B: 162, 486, 1458
Step-by-step explanation:
The given sequence is 2, 6, 18, 54, . . .
It is a geometric sequence and the common difference is 3.
The general form of a geometric sequence is: a, ar, ar², ar³, . . .
Here a = 2 and r = 3.
term of a Geometric progression is
.
Note that the fourth term is 54.
i.e., 
.
Similarly,
.
Also,
.
Hence, OPTION B is the answer.
Answer:
All real numbers greater than or equal to -3
Step-by-step explanation:
Notice for which values of the x-axis the function gives a well defined y-value (indicated by the trace of the curve in blue).
There is a solid dot at the point -3 for x and -2 for y, where the trace of the function begins. That means that the function is defined by f(-3) = -2.
and all x values to the right of -3 seem to also have a well defined y value f(x) that is represented by the blue curve.
Therefore, all x values starting at -3 (including it) and to the right (larger than -3) have well defined associated y values. Such constitutes the actual Domain of f(x).