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tatyana61 [14]
3 years ago
9

Solve the equations

Mathematics
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

#1 - All real numbers are solutions.

#2 - All real numbers are solutions.

Step-by-step explanation:

#1 -

Let's solve your equation step-by-step.

12(6t−4)=3t−2

Step 1: Simplify both sides of the equation.

12(6t−4)=3t−2

(12)(6t)+(12)(−4)=3t+−2(Distribute)

3t+−2=3t+−2

3t−2=3t−2

Step 2: Subtract 3t from both sides.

3t−2−3t=3t−2−3t

−2=−2

Step 3: Add 2 to both sides.

−2+2=−2+2

0=0

Same for #2

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Three consecutive numbers are such that when they are taken in increasing order and multiplied by 2,3and 4 respectively, they ad
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Answer:

7 , 8 , 9

Step-by-step explanation:

Assume three consecutive number are,

x , (x+1) , (x+2)

Multiplied by 2 ,3 and 4 respectively

2x , 3(x + 1) , 4(x + 2)

Sum of all = 74

So,

2x + 3(x + 1) + 4(x + 2) = 74

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3 years ago
Do the following lengths form a right triangle? ​
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Step-by-step explanation:

Because

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On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she ha
Sveta_85 [38]

Answer:

a. P(X=50)= 0.36

b. P(X≤75) =  0.9

c. P(X>50)=  0.48

d. P(X<100) = 0.9

Step-by-step explanation:

The given data is

x                      25        50       75        100          Total

P(x)                0.16       0.36    0.38    0.10          1.00

Where X is the variable and P(X) = probabililty of that variable.

From the above

a. P(X=50)= 0.36

We add the probabilities of the variable below and equal to 75

b. P(X≤75) = 0.16+ 0.36+ 0.38= 0.9

We find the probability of the variable greater than 50 and add it.

c. P(X>50)= 0.38+0.10=  0.48

It can be calculated in two ways. One is to subtract the probability of 100 from total probability of 1. And the other is to add the probabilities of all the variables less than 100 . Both would give the same answer.

d. P(X<100)= 1- P(X=100)= 1-0.1= 0.9

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Read 2 more answers
please solve this and show your work, no links/ ip grabbers PLEASE i’ve been asking this forever i just need the answer
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