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Tatiana [17]
3 years ago
6

Beth and joe won first place at the local talent show and shared the 50$ price equally they also gave some money to their friend

Romy if Beth and joe kept $20.75 how much money did they give Romy
Mathematics
1 answer:
swat323 years ago
8 0
If they each kept the same amount of the $50 prize, then we divide $50 by 2 people, giving each of them $25 winnings.  Your question is then a little confusing because it could be answered in two ways.  Did they each keep $20.75 out of their $25 winnings, or did the two of them keep $20.75 in a combined total?  Please read your question again to see which might be the case.  I'm answering on the assumption that they each kept $20.75.


STEP 1:
divide total prize money by 2

= $50 ÷ 2
= $25 each won


STEP 2:
If they each kept $20.75

= $25 won - $20.75 each kept
= $4.25 each gave away


STEP 3:
multiply amount given away by 2 people
= $4.25 * 2 people
= $8.50 total given away


ANSWER: The total given to Romy is $8.50.

Hope this helps!  :)
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ryan rides his bicycle 5 miles in 3/4 hour. how many miles can he ride at the same rate in 1 hour? (in fractions)​
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An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
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Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
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