Question

Part 1. determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.

Answer 1

The molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. is 5.23 gram.

What is an Ideal Gas ?

An Ideal Gas is a law for ideal gas which states that the product of Pressure and Volume is equal to the product of the moles of sample, universal gas constant and temperature.

PV = nRT

The given data in the question is

Pressure = 0.92 atm

Volume = 1.6 l

Temperature = 287 K

0.92 * 1.6 = n * 287 * 0.082

n = 0.06 moles

0.06 = 0.314 / molecular weight

molecular weight = 0.314/0.06

Molecular weight = 5.23 gm

Molar mass = 5.23 gm.

The  temperature and pressure conditions at which the gas behaves like an ideal gas is 273 K and 1 atm.

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