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Marat540 [252]
3 years ago
12

In the experiment the hydrogen gas is collected in a eudiometer tube over water. If the barometric pressure and the temperature

at the time of the experiment are 752.3 mm Hg and 21.6°C, respectively, and the vapor pressure of water at 21.6°C is 19.4 mm Hg, what is the pressure of the hydrogen gas in the eudiometer tube (in mmHg)?
Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

732.9 mmHg

Explanation:

At the eudiometer tube is the mixture of water and hydrogen gas (H₂), by Dalton's law of the partial pressure, the total pressure of a gas mixture (barometric pressure) is equal to the sum of the partial pressures of the components of the mixture:

Ptotal = Pwater + Phydrogen

752.3 = 19.4 + Phydrogen

Phydrogen = 752.3 - 19.4

Phydrogen = 732.9 mmHg

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4.2g of cerium reacted with oxygen to form 5.16g of an oxide of cerium. Find
olganol [36]

Answer:

CeO₂

Explanation:

Hello!

In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:

n_{Ce}=4.2gCe*\frac{1molCe}{140.12gCe}=0.03molCe\\

m_O=5.16g-4.2g=0.96gO\\\\n_O=0.96g*\frac{1molO}{16.0gO} =0.06molO

Now, we simply divide each moles by 0.03 as the fewest moles in the formula to obtain the simplest formula (empirical formula) of this oxide:

Ce=\frac{0.03}{0.03}=1\\\\O =\frac{0.06}{0.03}=2

Thus, the formula turns out:

CeO_2

Regards!

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