Answer:
The correct answer is C ions from the solute molecules have a strong attraction to the polar solvent molecules.
Explanation:
NaCl or Sodium chloride is an ionic compound which easily get dissolved in polar molecular compound such as water(H2O).
Both NaCl and H2O are polar compound because the atoms that forms NaCl and H2O have vast difference in their electronegativities.As a result the bonding electrons in both NaCl and H2O are not equally shared.
NaCl get dissolved in water molecules by dipole dipole interaction.
Elements of the same group show similar chemical properties as they have the same number of valence electrons. Sulfur belongs to the group 16 or 6 A or the oxygen family with 6 valence electrons. The elements of group 6 A are Oxygen, Sulfur, Selenium, Tellurium and Polonium. All of these elements show similar chemical properties. Therefore, when a biochemist studying the properties a sulfur containing biochemical compounds in the body wants to look at any other non-metal with similar properties, he has to consider other elements of the group 6 A like Oxygen (O), Selenium (Se), Tellurium (Te) and Polonium (Po).
molecules collide more frequently.
Chemical reaction mechanisms are based in the collision of molecules with certaing level of energy. More collisions implies grater probablity of reaction.
The percent yield of a chemical reaction is calculated by dividing the actual yield (determined through experimentation) by the theoretical yield (calculations). The percent yield is a great way of determining the efficiency of a reaction. For this problem, the percent yield is 83.93% as given by the solution:
% yield = (47/56)*100 = 83.93%
Answer: 429 grams of 
should be added to 1.3 L of water to prepare 2.0 M solution
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
where,
n = moles of solute = 
= volume of solution in Liters
Now put all the given values in the formula of molarity, we get
Therefore, 429 grams of should be added to 1.3 L of water to prepare 2.0 M solution
