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k0ka [10]
3 years ago
5

Ow many coulombs of charge are needed to produce 35.2 mol of solid zinc?

Chemistry
2 answers:
Natasha2012 [34]3 years ago
8 0
<span>Answer: Zn(2+) + 2e(-) -------> Zn 1 mole of Zn is deposited by 2F of electricity ... so 48.9 mole of Zn will be deposited by 48.9 X 2F = 97.8 F of electricity... as 1F = 96500 C so 97.8 F = 97.8 X 96500 = 9437700 C of electricity...</span>
JulijaS [17]3 years ago
3 0

Answer:

6.79 × 10⁶ c

Explanation:

Zn can be produced from the electrolysis of an aqueous solution of a Zn salt. The reduction reaction is:

Zn²⁺(aq) + 2 e⁻ → Zn(s)

We can establish the following relations.

  • 1 mol of Zn is produced when 2 moles of e⁻ are gained.
  • 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).

The charge needed to produce 35.2 mol of Zn is:

35.2molZn.\frac{2mole^{-} }{1molZn} .\frac{96468c}{1mole^{-}} =6.79 \times 10^{6} c

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Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution
frosja888 [35]

Answer:

0.6522 mol/L.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (no. of moles of solute)/(V of the solution (L)) </em>= (1.5 mol)/(2.3 L) = <em>0.6522 mol/L.</em>

7 0
3 years ago
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Calculate the pH of a solution prepared by mixing: (Show your work for these calculations) pk of acetic acid is 4.75 a. two mole
kupik [55]

Answer:

Explanation:

To calculate pH you need to use Henderson-Hasselbalch formula:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

Where HA is the acid concentration and A⁻ is the conjugate base concentration.

The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ \frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

a) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[2 mol]}

<em>pH = 4,75</em>

<em></em>

b) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[1mol]}

<em>pH = 5,05</em>

<em></em>

I hope it helps!

7 0
4 years ago
What is the molarity of a solution that contains 125 g nacl in 4.00 l solution?
bogdanovich [222]

Answer:

[NaCl[ = 0.535M

Explanation:

We determine the moles of solute:

125 g . 1 mol/ 58.45 g = 2.14 moles

Molarity (mol/L) → 2.14 mol / 4L → 0.535M

Molarity is a sort of concentration that indicates the moles of solute in 1L of solution

4 0
4 years ago
3. You are asked to prepare an aqueous solution. What would be a better choice for a solute potassium nitrate or
liubo4ka [24]

Answer:

i do not knowwww

Explanation:

8 0
3 years ago
If m = 45g and V = 15ml, what is D in g/ml?​
ch4aika [34]

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

6 0
3 years ago
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