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k0ka [10]
4 years ago
5

Ow many coulombs of charge are needed to produce 35.2 mol of solid zinc?

Chemistry
2 answers:
Natasha2012 [34]4 years ago
8 0
<span>Answer: Zn(2+) + 2e(-) -------> Zn 1 mole of Zn is deposited by 2F of electricity ... so 48.9 mole of Zn will be deposited by 48.9 X 2F = 97.8 F of electricity... as 1F = 96500 C so 97.8 F = 97.8 X 96500 = 9437700 C of electricity...</span>
JulijaS [17]4 years ago
3 0

Answer:

6.79 × 10⁶ c

Explanation:

Zn can be produced from the electrolysis of an aqueous solution of a Zn salt. The reduction reaction is:

Zn²⁺(aq) + 2 e⁻ → Zn(s)

We can establish the following relations.

  • 1 mol of Zn is produced when 2 moles of e⁻ are gained.
  • 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).

The charge needed to produce 35.2 mol of Zn is:

35.2molZn.\frac{2mole^{-} }{1molZn} .\frac{96468c}{1mole^{-}} =6.79 \times 10^{6} c

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A heating fan is supplied with 150 j of electricity which is nonverts to 113 j of thermal energy and 37 j of sound energy
Free_Kalibri [48]

Answer:

Heating Fan is 75.33% efficient.

Explanation:

As it is mentioned that the given fan is a HEATING FAN, it means the it is used for provided heat (thermal energy) to the surrounding. Hence, its efficiency depends upon how much heat/thermal energy is provides.

We can state that.

Total Energy provided = 150 J

Useful Energy = 113 J

Wasted Energy = 37 J

The efficiency of the heating fan can be given by following formula:

Efficiency = ( Useful Energy / Total Energy ) × 100

Efficiency = ( 113 J / 150 J) × 100

Efficiency = (0.7533)× 100

Efficiency = 75.33%

5 0
4 years ago
Ammonia (NH3) can be produced by the reaction of hydrogen gas with nitrogen gas:
VARVARA [1.3K]

Answer:

Percent yield = 61.5%

Explanation:

Given data:

Moles of hydrogen = 2.00 mol

Actual yield of ammonia= 0.80 mol

Percent yield = ?

Solution:

Chemical equation:

3H₂ + N₂ → 2NH₃

Now we will compare the moles of ammonia with hydrogen from balance chemical equation:

                     H₂       :       NH₃

                      3        :         2

                      2        :       2/3×2 = 1.3 mol

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 0.80 mol /1.3 mol × 100

Percent yield = 0.615 × 100

Percent yield = 61.5%

6 0
3 years ago
Sodium hydroxide + sulfuric acid​
trasher [3.6K]

Answer:

NaOH + H2SO4 ‐‐> 2H2O + Na2SO4;

4 0
3 years ago
Read 2 more answers
The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: st
Gelneren [198K]

Answer:

See explanation

Explanation:

The first step in this reaction is a unimolecular reaction. It involves the formation of the carbocation. This is so because tertiary alkyl halides only undergo substitution by SN1 mechanism due to sterric crowding.

The second step in the reaction is bi molecular. In this step, the carbocation now combines with the OH^- to yield the alcohol.

Net equation of the reaction is;

(CH3)3CBr + OH^- -------> (CH3)3COH + Br^-

The intermediate here is the carbocation,  (CH3)3C^+

8 0
3 years ago
Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of sodium sulfide and iron(II) nitrate
Luda [366]

Answer:

Fe^2+(aq) + S^2-(aq) --------> FeS(s)

Explanation:

First let us look at the molecular equation;

Na2S(aq) + Fe(NO3)2(aq) --------> FeS (s) + 2NaNO3(aq)

Now, the net ionic equation usually shows the most important reaction that took place, in this case, the formation of the FeS precipitate.

Hence, ionically;

Fe^2+(aq) + S^2-(aq) --------> FeS(s)

8 0
3 years ago
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