3 years ago

What type of asexual reproduction do bacteria most commonly use?

Chemistry

1 answer:

icang [17]3 years ago

3 0

Answer: Binary Fission

Explanation:

You might be interested in

Describe cold blooded animal.also some five example.

Vlad [161]

Answer:

Cold-blood animals are the animals that are not capable of regulating their body temperature,Cold blood animals included reptiles,fishes,amphibians,insects and other invertebrates.

3 0

2 years ago

Read 2 more answers

The atomic number of carbon is 6. carbon-14 is heavier than carbon-12 because the atomic nucleus of carbon-14 contains _____ neu

RSB [31]

14-6=8
8 neutrons is the answer

6 0

3 years ago

The first system of classification of organisms was developed by?

Margarita [4]

its the second one alright

5 0

3 years ago

Read 2 more answers

3. What do the most abundant elements in Earth's atmosphere have in common?

Advocard [28]

Answer:

They all have: nitrogen :780,900 755,100

oxygen: 209,500 231,500

argon 9,300 12,800

carbon dioxide

386 591

8 0

3 years ago

Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

Answer: The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

Explanation:

The given chemical equations follows:

Equation 1: $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

Equation 2: $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

7 0

3 years ago