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jasenka [17]
3 years ago
15

A sample of water with a mass of 622.7g undergoes a temperature change from 90.98°C

Chemistry
1 answer:
Dovator [93]3 years ago
6 0

Answer:

C) Q = 14888.5 J

Explanation:

  • Q = mCΔT

∴ m H2O = 622.7 g

∴ <em>C</em> H2O = 4.18 J/g°C

∴ ΔT= 96.7°C - 90.98°C = 5.72°C

⇒ Q = (622.7 g)(4.18 J/g°C)(5.72°C)

⇒ Q = 14888.508 J

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