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Katyanochek1 [597]
2 years ago
10

how long would it take to administer exactly 500 mL of fluid through an IV with a drop factor of 30 gtt/mL if the drip rate is 6

0 gtt/min?
Chemistry
1 answer:
Lyrx [107]2 years ago
7 0

Answer : The time taken will be 25 min.

Explanation :

First we have to determine the amount of fluid.

As, 1 mL contains 30 gtt

So, 500 mL contains \frac{500mL}{1mL}\times 30gtt=1500gtt

Now we have to determine the time taken.

As, 60 gtt takes time = 1 min

So, 1500 gtt takes time = \frac{1500gtt}{60gtt}\times 1min=25min

Therefore, the time taken will be 25 min.

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When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
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Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

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And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
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