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pochemuha
2 years ago
10

What is the percent yield if the quantity of reactants is sufficient to produce 0.86g of

Chemistry
1 answer:
Juliette [100K]2 years ago
8 0

Taking into account definition of percent yield, the percent yield for the reaction is 82.56%.

<h3>Definition of percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= \frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

  • actual yield= 0.71 grams
  • theorical yield= 0.86 grams

Replacing in the definition of percent yields:

percent yield= \frac{0.71 g}{0.86 g}x100

Solving:

<u><em>percent yield= 82.56%</em></u>

Finally, the percent yield for the reaction is 82.56%.

Learn more about percent yield:

brainly.com/question/14408642

#SPJ1

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Percentage yield = (actual yield / theoretical yield) x 100%<span>

The balanced equation for the reaction is,
    CH₄(g) + Cl₂<span>(g) </span>→ CH₃Cl(g) + HCl(g)</span><span>

Since there is excess of Cl₂ gas, we can assume that all of CH₄ gas are reacted.</span><span>

Moles of CH₄(g) = mass / molar mass</span><span>
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The stoichiometric ratio between CH₄(g) and CH₃Cl(g) is 1 : 1</span><span>

Hence moles of CH₃Cl(g) = 1.5625 mol</span><span>

Molar mass of CH₃Cl(g) = 50.5 g/mol</span><span>
 
Mass of CH₃Cl(g) = number of moles x molar mass</span><span>
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<span> Percentage yield = (45.0 g / 78.9 g) x 100% </span>
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