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4 years ago

Which of these pairs of elements is most likely to be part of a polyatomic ion?

Chemistry

2 answers:

Solnce55 [7]4 years ago

5 0

Answer: Option (d) is the correct answer.

Explanation:

A polyatomic ion is defined as the ion formed by two or more number of atoms which actually covalently combine together.

This means that only non-metals combine covalently together as a covalent bond is formed by sharing of electrons.

For example, S and O atoms are covalent and they tend to form polyatomic ions when combine together.

Whereas K and F, Li and I, Mg and Br are all metals and non-metals. So, they will always form an ionic bond as the metal will transfer its valence electrons to the non-metal.

Thus, we can conclude that out of the given options S and O pairs of elements is most likely to be part of a polyatomic ion.

Mrrafil [7]4 years ago

3 0

S and O would be on a polyatomic ion as I know of

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Ket [755]

Protons is the answer I think u are needing

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3 years ago

Read 2 more answers

A) How much energy would be required to melt 500 grams of ice at 0°C to water at 0°C?

baherus [9]

Heat required = Q = 40 kcal

<h3>Further explanation</h3>

Given

mass of 500 g ice

Required

Heat required

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)
Q = m.Lv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

Lf for water = 334 kj/kg=6.01 kJ/mol = 80 cal/g

Phase change(ice to water)

Q= 500 g x 80 cal/g

Q = 40 kcal

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3 years ago

Which of the following is in the formula for an acid?<br><br> H<br> OH-<br> hydroxide<br> oxide

avanturin [10]

A.) "Hydrogen" <span>is in the formula for an acid

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8 0

3 years ago

Read 2 more answers

½O2(g) + H2(g) ⇌ H2O(g)

ira [324]

Answer:

-241.826 kJ·mol⁻¹; -146.9 J·K⁻¹mol⁻¹; 664.6 J·K⁻¹mol⁻¹; spontaneous

Explanation:

½O₂(g) + H₂(g) ⟶ H₂O(g)

ΔHf°/kJ·mol⁻¹: 0 0 -241.826

S°/J·K⁻¹mol⁻¹: 205.0 130.6 188.7

1. ΔᵣH

ΔᵣH = products -reactants = -241.826 -(0 + 0) = -241.826 kJ·mol⁻¹

2. ΔᵣS

ΔᵣS = products - reactants = 188.7 - (205.0 + 130.6) = 188.7 - 335.6 = -146.9 J·K⁻¹mol⁻¹

3. ΔS(univ)

$\begin{array}{rcl}\Delta S_{\text{univ}} &=& \Delta S_{\text{sys}} +\Delta S_{\text{surr}}\\\\ &=& \Delta S_{\text{sys}} -\dfrac{\Delta H_{\text{sys}}}{T}\\\\& = & -146.9 - \dfrac{-241826}{298}\\\\& = & -146.9 + 811.5\\& = & \mathbf{664.6 \,\, J\cdot K^{-1}mol^{-1}}\\\end{array}$

4. Spontaneity

$\begin{array}{rcl}\Delta G &=& \Delta H - T\Delta S\\& = & -241.826 - 298 \times (-0.1469)\\& = & -241.826 + 43.776\\& = & \textbf{-198.050 kJ}\cdot\textbf{mol}^{\mathbf{-1}}\\\end{array}$

ΔG is negative, so the reaction is spontaneous.

4 0

3 years ago

The specific heat of water is 4.184Jg ∘C. Determine the final temperature when 600.0 g water at 75.5∘C absorbs 5.90×104 J of ene

sesenic [268]

Answer:

$T_2=98.5^{\circ}$

Explanation:

Given that,

The specific heat of water is 4.184Jg°C

Mass, m = 600 g

Initial temperature, T₁ = 75.5°C

We need to find the final temperature. We know that heat absorbed is given by :

$Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\\\T_2=\dfrac{Q}{mc}+T_1\\\\T_2=\dfrac{5.9\times 10^4}{600\times 4.184}+75\\\\T_2=98.5^{\circ}$

So, the final temperature is equal to $98.5^{\circ}$ .

3 0

3 years ago