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Vikentia [17]
3 years ago
11

C.Convert the following using the molar mass of each:

Chemistry
2 answers:
Alik [6]3 years ago
4 0

Answer:

1. 1.145 mole

2. 19.368g

3. 66.67 moles

4. 0.0056g

Explanation:

The following calculations gives the answers to the various questions asked above:

1. Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the question = 67g

Number of mole NaCl =.?

Number of mole = Mass /Molar Mass

Number of mole NaCl = 67/58.5

Number of mole of NaCl = 1.145 mol

2. Number of mole of H2O = 1.076 mole

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O =?

Mass = number of mole x molar Mass

Mass of H2O = 1.076 x 18

Mass of H2O = 19.368g

3. Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 1.2x104g

Mole of C6H12O6 =.?

Number of mole = Mass /Molar Mass

Mole of C6H12O6 = 1.2x104/180

Mole of C6H12O6 = 66.67 moles

4. Molar mass of Br2 = 2 x 80 = 160g/mol

Mole of Br2 = 3.5x10^-5 moles

Mass of Br2 =?

Mass = number of mole x molar Mass

Mass of Br2 = 3.5x10^-5 x 160

Mass of Br2 = 5.6x10^-3 = 0.0056g

MariettaO [177]3 years ago
4 0

Answer:

i)  1.15 moles NaCl

ii) 19.39 grams H2O

iii) 66.61 moles C6H12O6

iv)  0.00559 grams Br2

Explanation:

Step 1: data given

Molar mass = mass / moles

i.67 grams of NaCl to moles of NaCl

Moles = mass / molar mass

Moles NaCl = 67 grams / 58.44 g/mol

Moles NaCl = 1.15 moles NaCl

1.076 moles of H2O to grams of H2O

Mass H2O = 1.076 moles * 18.02 g/mol

Mass H2O = 19.39 grams H2O

1.2x104grams of C6H12O6to moles

Moles C6H12O6 = 12000 grams / 180.16 g/mol

Moles C6H12O6 = 66.61 moles C6H12O6

3.5x10-5 moles of Br2 to grams Br2

Mass Br2 = 3.5x10^-5 moles * 159.81 g/mol

Mass Br2 = 0.00559 grams Br2

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A sample of 10.6 g of KNO3 was dissolved in 251.0 g of water at 25 oC in a calorimeter. The final temperature of the solution wa
finlep [7]

Answer:

36.55kJ/mol

Explanation:

The heat of solution is the change in heat when the KNO3 dissolves in water:

KNO3(aq) → K+(aq) + NO3-(aq)

As the temperature decreases, the reaction is endothermic and the molar heat of solution is positive.

To solve the molar heat we need to find the moles of KNO3 dissolved and the change in heat as follows:

<em>Moles KNO3 -Molar mass: 101.1032g/mol-</em>

10.6g * (1mol/101.1032g) = 0.1048 moles KNO3

<em>Change in heat:</em>

q = m*S*ΔT

<em>Where q is heat in J,</em>

<em>m is the mass of the solution: 10.6g + 251.0g = 261.6g</em>

S is specififc heat of solution: 4.184J/g°C -Assuming is the same than pure water-

And ΔT is change in temperature: 25°C - 21.5°C = 3.5°C

q = 261.6g*4.184J/g°C*3.5°C

q = 3830.87J

<em>Molar heat of solution:</em>

3830.87J/0.1048 moles KNO3 =

36554J/mol =

<h3>36.55kJ/mol</h3>

<em />

6 0
2 years ago
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