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Advocard [28]
2 years ago
10

How much energy (in KJ) is needed to melt 15g of ice at -4oC and raise it to a temperature of 115oC? Round the closest number, a

nd include units
Chemistry
1 answer:
WARRIOR [948]2 years ago
4 0

Answer:

The energy needed is 45.7659 kJ

Explanation:

The given mass of the ice, m = 15 g

The initial temperature of the ice, T₁ = -4°C

The temperature

The final temperature, T₂ = 115°C

The specific heat capacity of ice, c₁ = 2.09 J/(g·°C)

The latent heat of ice, l₁ = 334 J/g

The heat capacity of water, c₂ = 4.184 J/(g·°C)

The latent heat of vaporization, l₂ = 2260 J/g

The specific heat of steam, c₃ = 2.02 J/g

Therefore, we get the energy needed, ΔQ, as follows;

ΔQ = m·c₁·(T₂ - Tₐ) + m·l₁ + m·c₂(Tₓ - Tₐ) + m·l₂ + m·c₃·(T₂ - Tₓ)

Where;

Tₐ = The melting point temperature of water = 0°C

Tₓ = The boiling point temperature of water = 100°C

∴ ΔQ = 15×2.09×(0 - (-4)) + 15 × 334 + 15×4.184×(100 - 0) + 15×2260 + 15×2.02×(115 - 100) = 45,765.9

The energy needed, ΔQ = 45,765.9 J = 45.7659 kJ.

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Answer:

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Explanation:

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Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

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Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

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Step 3: Calculate number of moles

Moles = mass / molar mass

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Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

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Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

Molality = number of moles / mass

Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

Molality of toluene = 3.08 molal

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