Question

A car and an SUV both hit a patch of ice while driving eastbound down the road. The 1200-kg car was moving at 5 m/s when the 2600-kg SUV hit it from behind at a speed of 12 m/s. Upon impact, the car veers off the side of the road at a speed of 10 m/s. The SUV continues forward at its new velocity. Calculate the final speed of the SUV.
Velocity: _ m/s

Answer 1

The final speed of the SUV given the data from the question is 9.79 m/s

Data obtained from the question

• Mass of car (m₁) = 1200 Kg
• Velocity of car (v₁) = 5 m/s
• Mass of SUV (m₂) = 2600 Kg
• Velocity of SUV (v₂) = 12 m/s
• Final velocity (v) =?

How to determine the final velocity of SUV

From conservative of linear momentum,

momentum before impart = momentum after impart

m₁v₁ + m₂v₂ = v(m₁ + m₂)

Thus, we shall determine the final velocity of the SUV by obtaining the velocity after impart. This can be obtained as follow:

v = (m₁v₁ + m₂v₂) / (m₁ + m₂)

v = [(1200 × 5) + (2600 × 12)] / (1200 + 2600)

v = [(6000 + 31200)] / 3800

v = 37200 / 3800

v = 9.79 m/s

Thus, the final velocity of the SUV is 9.79 m/s

Learn more about momentum:

brainly.com/question/250648

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