NEED HELP ASAP

Pls help ASAP !! Phyics

mina [271]

Answer:

Explanation:

Given

mass (m)= 20 kg

acceleration (a)= 10 m/s^2

Force (f)= m a

= 20 * 10

= 200 N

7 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

maria [59]

Answer:

a) a = 5.03x10¹³ m/s²

b) $V_{f} = 4.4 \cdot 10^{5} m/s$

Explanation:

a) The acceleration of the positron can be found as follows:

$F = q*E$ (1)

Also,

$F = ma$ (2)

By entering equation (1) into (2), we have:

$a = \frac{F}{m} = \frac{qE}{m}$

Where:

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C

E: is the electric field = 286 N/C

$a = \frac{qE}{m} = \frac{1.6 \cdot 10^{-19} C*286 N/C}{9.1 \cdot 10^{-31} kg} = 5.03 \cdot 10^{13} m/s^{2}$

b) The positron's speed can be calculated using the following equation:

$V_{f} = V_{0} + at$

Where:

$V_{f}$ : is the final speed =?

$V_{0}$ : is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

$V_{f} = V_{0} + at = 0 + 5.03 \cdot 10^{13} m/s^{2}*8.70 \cdot 10^{-9} s = 4.4 \cdot 10^{5} m/s$

I hope it helps you!

4 0

3 years ago

. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

kupik [55]

Answer:

(c) 16 m/s²

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of r(t).

$v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since a(t) does not have the variable t, it is constant. Hence, at any time,

$a = -16\hat{j}$

Its magnitude is 16 m/s².

4 0

3 years ago

Solve the following two equations for the (positive) time, t, and the position, x. Assume SI units.

Luden [163]

A system of equations is a group of equations with the same variables that we need to solve simultaneously. Such that the solutions is given by the intersection betweens graphs of the functions.

We will see that the solution is (16.4, 807.0)

Here the system is:

$x = 3.00*t^2\\x = 45.0*t + 69.0$

To solve a system we usually need to isolate one of the variables in one equation and replace that in the other equation, here we already see that we have x isolated in the two equations, so we can write:

$3.00*t^2 = x = 45.0*t + 69.0\\3.00*t^2 = 45.0*t + 69.0$

Now we can solve the above equation for t:

$3.00*t^2 = 45.0*t + 69.0\\\\3.00*t^2 - 45.0*t - 69.0 = 0$

This is just a quadratic equation, the solution is given by the Bhaskara's formula, we will get:

$t = \frac{-(-45.0) \pm \sqrt{(-45.0)^2 - 4*(3.00)*(-69.0)} }{2*3.00} \\\\t = \frac{{(45.0) \pm 53.4} }{6.00}$

Then the two values of t are:

t = (45.0 + 53.4)/6 = 16.4

t = (45.0 - 53.4)/6 = -1.4

We want the positive solution, so we choose t = 16.4

To complete the solution we need to evaluate one of our functions in this time. Let's use the first one:

x = 45.0*16.4 + 69.0 = 807.0

Then the solution is:

(16.4, 807.0)

If you want to learn more you can read:

brainly.com/question/12895249

5 0

3 years ago

What can make your computer "sick"?

Svetach [21]

Answer:

An virus

Explanation:

An computer virus can come from websites that try to steal your Information or apps that's not necessarily scanned and protected so that yor computer can be safe from viruses.

7 0

3 years ago