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3 years ago

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Which of these objects would need the largest force to create an

1 answer:

Gnom [1K]3 years ago

6 0

Newton's second law for an object's motion in one spatial dimension:

F = ma

F is the force, m is the mass, and a is the acceleration.

From this equation, we can tell that, compared to a less massive object, a more massive object will need a bigger force to make it accelerate at the same rate. The 30kg sofa has the most mass out of all the above listed objects, therefore it will take the biggest force to accelerate at 1m/s²

Choice D

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Which color has the lowest frequency?

Svet_ta [14]

<h2>RED!</h2><h3></h3><h3>On the visible spectrum, red has the lowest frequency.</h3><h3>(I'm an amateur astronomer, so I would know.)</h3>

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2 years ago

Through what process does water leave the hydrosphere and enter the atmosphere

evablogger [386]

Water<span> and the </span>atmosphere<span>. </span>Water enters the atmosphere through<span> evaporation, transpiration, excretion and sublimation: Transpiration is the loss of </span>water<span> from plants (</span>via<span> their leaves).</span>

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3 years ago

A right-circular cylindrical tank of height 8 ft and radius 4 ft is laying horizontally and is full of fuel weighing 52 lb/ft3

tresset_1 [31]

Given:

Height of tank = 8 ft

and we need to pump fuel weighing 52 lb/ $ft^{3}$ to a height of 13 ft above the tank top

Solution:

Total height = 8+13 =21 ft

pumping dist = 21 - y

Area of cross-section = $\pi r^{2}$ = $\pi 4^{2}$ =16 $\pi$ $ft^{2}$

Now,

Work done required = $\int_{0}^{8} 52\times 16\pi (21 - y)dy$

= $832\pi \int_{0}^{8} (21 - y)dy$

= 832 $\pi($ $[ 21y ]_{0}^{8} - [\frac{y^{2}}{2}]_{0}^{8}\\$ )

= 113152 $\pi$ = 355477 ft-lb

Therefore work required to pump the fuel is 355477 ft-lb

7 0

3 years ago

Will mark as BRAINLIEST.......

irinina [24]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

$x=4t^3+3t^2-5t+2$

Where,

x is in meters and t is in sec

We know that,

Velocity,

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5$

(a) i. t = 2 s

$v=12(2)^2+6(2)-5=55\ m/s$

At t = 4 s

$v=12(4)^2+6(4)-5=211\ m/s$

(b) Acceleration,

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6$

Pu t = 3 s in above equation

So,

$a=24(3)+6\\\\a=78\ m/s^2$

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

6 0

3 years ago

Ford used to make a 7.0 liter engine. Calculate how many many cubic inches would be the same size engine.

Anestetic [448]

Answer : The volume of engine in cubic inches is, $427.166\text{ inch}^3$

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

$1\text{ liter}=1000cm^3$

So, $7\text{ liter}=7000cm^3$

$1\text{ inch}=2.54cm$

or,

$1cm=\frac{1}{2.54}\text{ inch}$

$1cm^3=(\frac{1}{2.54}\text{ inch})^3$

As,

$1cm^3=(\frac{1}{2.54}\text{ inch})^3$

So,

$7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3$

Thu, the volume of engine in cubic inches is, $427.166\text{ inch}^3$

3 0

3 years ago