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Ber [7]
3 years ago
13

Which of these objects would need the largest force to create an

Physics
1 answer:
Gnom [1K]3 years ago
6 0

Newton's second law for an object's motion in one spatial dimension:

F = ma

F is the force, m is the mass, and a is the acceleration.

From this equation, we can tell that, compared to a less massive object, a more massive object will need a bigger force to make it accelerate at the same rate. The 30kg sofa has the most mass out of all the above listed objects, therefore it will take the biggest force to accelerate at 1m/s²

Choice D

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Statement A: Area of a rectangle with measured length = 2.536 m and width = 1.4 m. Statement B: Area of a rectangle with measure
Sholpan [36]

Answer:

Statement A=3.5504m²

Statement B=3.57576m²

Explanation:

The area of a rectangle is gotten by multiplying the length of the rectangle by the width of the rectangle which gives us the surface area which the rectangle covers. For statement A, I multiplied 2.536 by 1.4 and for statement B, I multiplied 2.536 by 1.41

7 0
3 years ago
Which of the following is a FALSE statement? A. Heat moves through solids by conduction. B. Molecules move faster in warmer subs
matrenka [14]
C is the FALSE statement.
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3 years ago
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Loghan and Kyle wanted to see if the type of ice cream in the freezer affects how hard or soft it is. At three different times,
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Loghan and Kyle should have use the same type of ice cream for all three ice cream containers to get a more accurate result and data
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3 years ago
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A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th
GREYUIT [131]

Answer:

1.26\cdot 10^7 m/s

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

F=qvB

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

v=\frac{qBr}{m}

where in this problem we have:

q=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

B=208 G=208\cdot 10^{-4}T is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

r=3.45 mm = 3.45\cdot 10^{-3} m

m=9.11\cdot 10^{-31} kg is the mass of the electron

So, the electron's speed is

v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s

6 0
3 years ago
In a horizontal pipe with a gradually decreasing cross-section (in the direction of flow) there is a clear fluid of unknown dens
qwelly [4]

Answer:

the density of this clear fluid is 1140.35 kg/m^3

Explanation:

Given that :

P_p = P__{Q}} + 260 \ Pa \\ \\ v_p =0.37 \ m/s \\ \\ v_Q = 0.77 \ m/s

According to Bernoulli's Equation.

P_p + \frac{1}{2} pv^2_p+pgh_p= P_Q+ \frac{1}{2} pv^2_Q + pgh_Q

∴ 260 = \frac{1}{2}p (v^2_Q-v^2_p)      since ( h_p = h_Q)

\rho = \frac{2(260)}{v^2_Q-v^2_p}

\rho = \frac{2(260)}{0.77^2-0.37^2}

\rho = \frac{520}{0.5929-0.1369}

\rho = 1140.35 \  kg/m^3

5 0
4 years ago
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