Answer:
<u>Lateral Surface Area</u>: The total surface area of a three-dimensional object, excluding the bases.
<h3><u>Question 5</u></h3>
Figure: <u>Rectangular prism</u>
Given:
- length (
) = 10 m - width (
) = 4 m - height (
) = 6 m
<u>Lateral Surface Area</u>

<u>Total Surface Area</u>

<u>Volume</u>

<h3><u>Question 6</u></h3>
Figure: <u>Triangular Prism</u>
The <u>bases</u> of a triangular prism are the <u>triangles.</u>
<u />
First, find the hypotenuse of the right triangular base using Pythagoras' Theorem
where a and b are the legs and c is the hypotenuse.



<u>Lateral Surface Area</u>
The L.A. is made up of 3 rectangles, each with a length of 12 ft and a width of one side of the triangular base.

<u>Total Surface Area</u>
The T.A. is made up of the L.A. plus the areas of the triangular bases.


<u>Volume</u>
