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Airida [17]
3 years ago
7

The price of some houses in a neighborhood are shown below: House Price A $120,000 B $130,000 C $140,000 D $150,000 E $1,110,000

Based on the data, should the mean or the median be used to make an inference about the price of the houses in the neighborhood? A) Median, because there is an outlier that affects the mean B) Mean, because there are no outliers that affect the mean C)Median, because it is in the center of the data D) Mean, because it is in the center of the data
Mathematics
2 answers:
MissTica3 years ago
8 0
In my opinion I would use the mean. But the options that are given I would choose answer A. But I'm not 100% sure.
bogdanovich [222]3 years ago
5 0

Answer: Median, because there is an outlier that affects the mean.

Step-by-step explanation:

The outlier is 1,110,000

As you have learned in the lesson, outliers affect means, meaning that you should not use them.

Hope this helped! ❤

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anyanavicka [17]

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Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

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Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

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\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

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Answer:

PQR=1

Step-by-step explanation:

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