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torisob [31]
2 years ago
13

Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be u

sed. Roy and Elisa are buying tickets for the annual school concert. Roy buys 6 adult tickets and 2 child tickets for a total of $66. Elisa buys 5 adult tickets and 4 child tickets for a total of $62. Determine the system of equations that can be used to find the cost of one adult ticket, a, and the cost of one child ticket, c.
62 5 128 6 4 66 2 8
Roy:__a + __c =__
Elisa:__a+__c =__
Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let's consider adults tickets be a and child tickets be c

so

Roy's purchase

6a+2c=66------1

Elisa's purchase

5a+4c=62-------2

Hence,  the system of equations

6a+2c=66------1

5a+4c=62-------2

solving simultaneously

6a+2c=66

5a+4c=62

Also,

 12a+4c=132

-5a+4c=62

  7a=70

a=$10

put  a=70 in 1

6(10)+2c=66

60+2c=66

2c=66-60

2c=6

c=$3

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

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the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
What is the median of the data?<br><br> 3<br> 8<br> 5<br> 5.5
ladessa [460]

Answer:

Median= middle number

(Example) 1, 4 ,6, 7 ,12

6 Would be the median here

so, 3, 3, 4, 4, 5, 5, 5, 5, 6, 7, 8,

5 Is the middle number and the median

Step-by-step explanation:

6 0
3 years ago
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Use the function y=3/2x+3 to complete the table of values
anastassius [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

Putting all the values of y=9, 6, 0, and -3 to complete the table

FOR y=9

putting y=9

switch sides

subtract 3 from both sides

Hence,

when y=9, x=4

FOR y=6

putting y=6

switch sides

subtract 3 from both sides

Hence,

when y=6, x=2

FOR y=0

putting y=0

switch sides

subtract 3 from both sides

Hence,

when y=0, x=-2

FOR y=-3

putting y=-3

switch sides

subtract 3 from both sides

Hence,

when y=-3, x=-4

Hence, the table becomes:

x                     y

9                    4

6                    2

0                    -2

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GrogVix [38]
The ? is 1. 

7*(9*1)=63

Hope this helps!!
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sergiy2304 [10]

That question is accompanied by these answer choices:

<span>A. The scale is accurate but not precise.
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C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.

Then you need to distinguish between accuracy and precision.

Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.

The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.

So, the answer is that the scale is precise but not accurate (the option B</span>
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