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torisob [31]
2 years ago
13

Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be u

sed. Roy and Elisa are buying tickets for the annual school concert. Roy buys 6 adult tickets and 2 child tickets for a total of $66. Elisa buys 5 adult tickets and 4 child tickets for a total of $62. Determine the system of equations that can be used to find the cost of one adult ticket, a, and the cost of one child ticket, c.
62 5 128 6 4 66 2 8
Roy:__a + __c =__
Elisa:__a+__c =__
Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let's consider adults tickets be a and child tickets be c

so

Roy's purchase

6a+2c=66------1

Elisa's purchase

5a+4c=62-------2

Hence,  the system of equations

6a+2c=66------1

5a+4c=62-------2

solving simultaneously

6a+2c=66

5a+4c=62

Also,

 12a+4c=132

-5a+4c=62

  7a=70

a=$10

put  a=70 in 1

6(10)+2c=66

60+2c=66

2c=66-60

2c=6

c=$3

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

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WARRIOR [948]

Answer:

b = 2

Step-by-step explanation:

In order to find the value of b, we have to isolate b on one side of equation first

So,

3b+2(b-1)=8

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3b+2b-2=8\\5b-2=8

Adding 2 on both sides

5b-2+2=8+2\\5b=10

Dividing by 5 on both sides

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3 years ago
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a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

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<span>Solve for x
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