Answer:
20%?
Step-by-step explanation:
idk lol im pretty sure thats it
Problema Solution
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?
Answer provided by our tutors
Make a drawing and denote:
x = half of the length of the enclosure
2x = the length of the enclosure
y = the width of the enclosure
P = 800 ft the perimeter
The perimeter of the two enclosures can be expressed P = 4x + 2y thus
4x + 3y = 800
Solving for y:
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y = 800/3 - 4x/3
The area of the two enclosure is A = 2xy.
Substituting y = 800/3 - 4x/3 in A = 2xy we get
A = 2x(800/3 - 4x/3)
A =1600x/3 - 8x^2/3
We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum:
x max = -b/2a, a = (-8/3), b = 1600/3
x max = (-1600/3)/(2*(-8/3))
x max = 100 ft
y = 800/3 - 4*100/3
y = 133.33 ft
2x = 2*100
2x = 200 ft
To solve this, take the total distance (5,280) divide by the average step (42).
5,280/42 = 125.714
We first need to find the distance.
The information about Mike will provide the distance we need to answer the question about Pedro.
We will use D = rt
Mike:
(6.5)((17/5) = D
22.1 miles = D
Pedro:
D = rt
22.1 = (19/5)t
We need to find t.
22.1 ÷ 3.8 = t
5.8157894737 = t
We now round off as instructed.
5.82 = t
It took Pedro 5.82 hours to reach the lake.
The first from right 8*3=24
72*3=216
216*3=648
648*3=1944
1944*3=5832
