First of all we have to arrange the data in ascending order as shown below:

28, 40, 43, 43, 45, 50, 50

Total number of values = 7

Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:

1st Half = 28, 40, 43
2nd Half = 45, 50, 50

Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.

IQR or the Inter Quartile Range is the difference of Q3 and Q1.

So, IQR= Q3 – Q1 = 50 – 40 = 10

Thus, IQR for the given data is 10

4 0

3 years ago

Read 2 more answers

Hello! I need some help figuring out the following parts of trigonometry. Since this is a rather difficult math term to understa

Zina [86]

Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:
SOH
CAH
TOA

This means:
Sine --> Opposite/Hypotenuse
Cosine --> Adjacent/Hypotenuse
Tangent --> Oppositie/Adjacent

With that in mind, number 1:
Would be Sine, or C.

Number 2 would be, Cosine, or E.

And number 3 would be Tangent, or B.

Hope that was helpful.

4 0

3 years ago

Read 2 more answers

Graph the inverse circular function by hand, given f(x) = 3sin(2x) ;-pi/4 ≤ ≤pi/4

nasty-shy [4]

Part a)

a) The given function is

$f(x) = 3 \sin(2x)$