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Sauron [17]
1 year ago
5

Based on a​ poll, 66​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is

the probability that among 3 randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond?
Mathematics
1 answer:
Harlamova29_29 [7]1 year ago
5 0

Answer:

.

Step-by-step explanation:

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The top tree broke and fell over.the remaining tree teunk is 3 feet tall.the tip of the tree rests on the ground 14 feet from th
Bas_tet [7]

Answer:

14.3 feet.

14.3 feet

Step-by-step explanation:

The problem forms a right triangle in which:

The Vertical Leg of the Right Triangle = 3 feet

The Horizontal Leg of the Right Triangle =14 feet

We are to determine the length of the broken part of the tree. This is the Hypotenuse of the Right Triangle,

Using Pythagoras Theorem

Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=14^2+3^2\\Hypotenuse^2=205\\Hypotenuse=\sqrt{205}\\Hypotenuse=14.32\\ \approx 14.3 feet $(to the nearest tenth of a foot).\\Therefore, the lenght of the broken part of the tree to the nearest tenth of a foot is 14.3 feet.

5 0
3 years ago
Change the equation from standard form to slope-intercept form -5x-2y=-3
horrorfan [7]

Answer:Your Mom

<h2>Step-by-step explanation:Cause she is fat No but it srsly is 123</h2>
5 0
3 years ago
3/10+2 1/10+5 1/10 I need help
forsale [732]
The answer is 7.5for the question
7 0
3 years ago
Plzz HELP FOR POINTS AND BRAINLIST ANSWER
storchak [24]

A)Plugging in our initial statement values of y = 16 when x = 10, we get:

16 = 10k

Divide each side by 10 to solve for k:

16/10=

 k = 1.6

Solve the second part of the variation equation:

Because we have found our relationship constant k = 1.6, we form our new variation equation:

y = 1.6x

Since we were given that x, we have

y = 1.6()

y = 0


B)Plugging in our initial statement values of y = 1 when x = 15, we get:

1 = 15k

Divide each side by 15 to solve for k:

1/15

=15k

k = 0.066666666666667

7 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
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