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3 years ago

Solve using distributive property. 2(3 + 4)

Mathematics

1 answer:

STatiana [176]3 years ago

7 0

Answer:

it would be 14

Step-by-step explanation:

you have to simplify the expressions

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A line includes the points (4,1) and (8, 2). What is its equation in slope-intercept form?

kobusy [5.1K]

Answer:

y=1/4x

Step-by-step explanation:

y=mx+b slope is m rise over run 4 over 1 up so 1/4 then to find y intercept apply slope y int is 0

7 0

3 years ago

Circle towns limit form a perfectly circular shape that has a population of 20000 in the population density of 480 people per sq

Alex

Answer:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

Step-by-step explanation:

For this case we know the population size $P = 20000$ and we also know the population density $D = 480 \frac{people}{km^2}$

We can assume that the area is a circle. We also know that the formula for the population density is given by:

$D= \frac{P}{A}$

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

$A = \pi X^2$

With X the radius of the circle

And then the populationd density become:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

6 0

4 years ago

Please say me the answer fast with step by step process

zepelin [54]

Yes I’m sorry but I’m sorry I’m texting back to my sister in

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3 years ago

Find the diameter of a circle if the radius is equal to 8?

Andru [333]

The diameter is 16 so that is the answer<span />

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3 years ago

Need help now!! 20 points!!

Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0

3 years ago