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Sergio [31]
2 years ago
9

Hydrogen and iodine gas react to form hydrogen iodide, as shown in the equation H2(g) + I2(g) → 2HI(g). Suppose you are given a

time interval from t1 = 10 seconds to t2 = 20 seconds and a change in H2 concentration from0.210 mol/L to 0.185 mol/L. Use the reaction rate equation to calculate the average reaction rate during that time period. Show your work.
Chemistry
1 answer:
Leona [35]2 years ago
5 0

The average reaction rate during that time period is 0.0025 mol/l.

<h3>What is concentration?</h3>

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

t_1 = 10 seconds

t_2 = 20 seconds

C_1 = 0.210 mol/L

C_2 = 0.185 mol/L

∆C = |C_2–C_1| = |0.185-0.21| = 0.025 mol/l

∆t = t_2– t_1 = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  \frac{\Delta C}{\Delta t} = \frac {0.025}{10}= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

Learn more about the concentration here:

brainly.com/question/10725862

#SPJ1

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How many milliliters of 0.200 M NH4OH are needed to react with 12.0 mL of 0.550 M FeCl3?
trapecia [35]

Answer:

9.9 ml of 0.200M NH₄OH(aq)

Explanation:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

?ml of 0.200M NH₄OH(aq) reacts completely with  12ml of 0.550M FeCl₃(aq)

1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution

1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)

=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters  

5 0
3 years ago
How is bohrs model of the atom arranged? where the protons? nuetrons? electrons?
atroni [7]
The bohr model is arranged so there is a nucleus in the middle that holds the neutrons and protons. Around the nucleus, there is shells or energy levels that hold electrons in a formation of 2,8,8.
5 0
3 years ago
Read 2 more answers
When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of
baherus [9]
When dT = Kf * molality * i
                = Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
                               = 2.5g /250g x 1 mol /85 g x1000g/kg
                               =0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution 
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and  i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
     = (0.1176 * 0.359)^2 / (1-0.359)
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5 0
3 years ago
How many molecules are in
diamong [38]

Answer:

3.6 × 10²⁴ molecules

Explanation:

Step 1: Given data

Moles of methane (n): 6.0 moles

Step 2: Calculate the number of molecules of methane in 6.0 moles of methane

In order to convert moles to molecules, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ molecules of methane in 1 mole of molecules of methane.

6.0 mol × 6.02 × 10²³ molecules/1 mol = 3.6 × 10²⁴ molecules

6 0
3 years ago
Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
mash [69]

Answer:

              10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

   H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH  →  H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

    88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) Ethyl Butyrate

So,

           8.25 g Butanoic Acid will produce  =  X g of Ethyl Butyrate

Solving for X,

                      X =  (8.25 g × 116.16 g) ÷ 88.11 g

                      X =  10.87 g of Ethyl Butyrate

8 0
3 years ago
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