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Sergio [31]
1 year ago
9

Hydrogen and iodine gas react to form hydrogen iodide, as shown in the equation H2(g) + I2(g) → 2HI(g). Suppose you are given a

time interval from t1 = 10 seconds to t2 = 20 seconds and a change in H2 concentration from0.210 mol/L to 0.185 mol/L. Use the reaction rate equation to calculate the average reaction rate during that time period. Show your work.
Chemistry
1 answer:
Leona [35]1 year ago
5 0

The average reaction rate during that time period is 0.0025 mol/l.

<h3>What is concentration?</h3>

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

t_1 = 10 seconds

t_2 = 20 seconds

C_1 = 0.210 mol/L

C_2 = 0.185 mol/L

∆C = |C_2–C_1| = |0.185-0.21| = 0.025 mol/l

∆t = t_2– t_1 = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  \frac{\Delta C}{\Delta t} = \frac {0.025}{10}= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

Learn more about the concentration here:

brainly.com/question/10725862

#SPJ1

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The diagram below helps to solidify the points made above.

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Which of the following elements is the most reactive?<br> A. At<br> B.Cl<br> C.I<br> D.Br
adell [148]

Answer:

B.  Cl.

Explanation:

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6 0
2 years ago
Balloon A started with a volume of 1.76 L. The temperature of the room the balloon was in was 295 K. The balloon was heated to a
valentina_108 [34]

Answer:

V₂ = 1.5 L

Explanation:

Given data:

Initial volume of balloon = 1.76 L

Initial temperature = 295 K

Final temperature = 253.15 K

Final volume = ?

Solution:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.76 L ×253.15 K / 295 K

V₂ = 445.54 L.K /295 K

V₂ = 1.5 L

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You used a variety of media with a NaCl concentration ranging from 0.5% to 15%. Which of these media would have the lowest water
Studentka2010 [4]

Answer:

Explanation:

B

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