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Sergio [31]
1 year ago
9

Hydrogen and iodine gas react to form hydrogen iodide, as shown in the equation H2(g) + I2(g) → 2HI(g). Suppose you are given a

time interval from t1 = 10 seconds to t2 = 20 seconds and a change in H2 concentration from0.210 mol/L to 0.185 mol/L. Use the reaction rate equation to calculate the average reaction rate during that time period. Show your work.
Chemistry
1 answer:
Leona [35]1 year ago
5 0

The average reaction rate during that time period is 0.0025 mol/l.

<h3>What is concentration?</h3>

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

t_1 = 10 seconds

t_2 = 20 seconds

C_1 = 0.210 mol/L

C_2 = 0.185 mol/L

∆C = |C_2–C_1| = |0.185-0.21| = 0.025 mol/l

∆t = t_2– t_1 = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  \frac{\Delta C}{\Delta t} = \frac {0.025}{10}= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

Learn more about the concentration here:

brainly.com/question/10725862

#SPJ1

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4 0
2 years ago
If 316 mL nitrogen is combined with 178 mL oxygen, what volume of N2O is produced at constant temperature and pressure if the re
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Answer;

=259 ml

Explanation;

-According to Gay Lussac's Law of Combining Volumes when gases react, they do so in volumes which have a simple ratio to one another, and to the volume of the product formed if gaseous, provided the temperature and pressure remain constant.

-Thus; from the volume of nitrogen and oxygen gases; we have; 316 / 178 = 1.775 moles of nitrogen gas per mole of oxygen gas.

-Therefore, nitrogen gas is the limiting reactant, and for each mole of nitrogen gas used, we will get 1 mole of N2O. This means the resulting volume of N2O with 100% yield will be the same as the volume of nitrogen gas used, thus, 100% yield will produce 316 mL.

However, with 82% yield the volume would be; 316 × 82/100 =259 ml

Therefore; the volume of N2O at 82% yield will be 259 ml

7 0
3 years ago
Read 2 more answers
What is the ratio between the mass of nitrogen and oxygen in N2O3?
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Answer:

12:7

Explanation:

To Determine: To calculate the formula of the unknown binary compound of oxygen and nitrogen and to ratio in the next compound of the series using given data.Answer:The formula of the unknown compound .The ratio for atoms of oxygen to nitrogen inis .The mass ratio of oxygen to nitrogen in next member of the series of compounds is .Explanation:The mass ratio of toinis .The mass ratio of toin theunknown compound is .The atomic mass of the oxygen is .The atomic mass of the nitrogen is .The mass ratio of to in a molecule can be represented as: …… (1)Here,is the number of atoms of the oxygen in the molecule.is the mass of an atom of oxygen.is the number of atoms of the nitrogen in the molecule.is the mass of an atom of nitrogen.For unknown compound, substitutefor , for and for mass ratio in equation (1).The ratio of atoms of oxygen to nitrogen is , therefore, the expected formulas of the unknown compound is and . If the unknown compound is in a series with then the formula of the unknown compound and the formula for the next member of the series is .The ratio for atoms of oxygen to nitrogen inis .For , substitute 5 for , for , 2 for and for in equation (1).The mass ratio of oxygen to nitrogen in next member of the series of the compounds is .

6 0
3 years ago
What is the product of the following chemical equation?
g100num [7]

Answer: carbon dioxide and water

Explanation:

C3H8 + 5O2 —> 3CO2 + 4H2O

6 0
2 years ago
She dissolves a 10.0mg sample in enough water to make 30.0mL of solution. The osmotic pressure of the solution is 0.340torr at 2
uranmaximum [27]

Answer:

(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

(b)The freezing point for the aqueous solution is -3.413\times10^{-5} C

Explanation:

The osmotic pressure (π) is given by the following equation:

\pi =cRT

c= Concentration of solution

R = universal gas constant = 62.364 \frac{L\times torr}{mol\times K}

T = temperature

Weight of solute = w = 10.0 mg

Let the molecular weight of the solute be m g/mol.

Concentration = c=\frac{n}{V}\\ n=\frac{w}{m}\\ n=\frac{10\times10^{-3}}{m}\\c=\frac{10\times10^{-3}}{m\times30\times10^{-3}}M

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Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

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m is the molality of the solution.

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\Delta T_{f}=1.86\times m

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The freezing point for the aqueous solution is -3.413\times10^{-5} C

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