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Sergio [31]
1 year ago
9

Hydrogen and iodine gas react to form hydrogen iodide, as shown in the equation H2(g) + I2(g) → 2HI(g). Suppose you are given a

time interval from t1 = 10 seconds to t2 = 20 seconds and a change in H2 concentration from0.210 mol/L to 0.185 mol/L. Use the reaction rate equation to calculate the average reaction rate during that time period. Show your work.
Chemistry
1 answer:
Leona [35]1 year ago
5 0

The average reaction rate during that time period is 0.0025 mol/l.

<h3>What is concentration?</h3>

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

t_1 = 10 seconds

t_2 = 20 seconds

C_1 = 0.210 mol/L

C_2 = 0.185 mol/L

∆C = |C_2–C_1| = |0.185-0.21| = 0.025 mol/l

∆t = t_2– t_1 = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  \frac{\Delta C}{\Delta t} = \frac {0.025}{10}= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

Learn more about the concentration here:

brainly.com/question/10725862

#SPJ1

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Explanation:

According to the law of conservation of mass, mass can neither be created nor it can be destroyed. But it can be simply transformed from one form to another.

Therefore, when AgNO_{3} is added to NaCl then the compound formed will have same mass as that of reactants.

       AgNO_{3} + NaCl \rightarrow AgCl + NaNO_{3}

Total mass of reactants is (169.87 + 58.44) g/mol = 228.31 g/mol

Total mass of products is (143.32 + 84.99) g/mol = 228.31 g/mol

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if you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?
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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
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Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

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Answer:

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Explaination

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