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Sergio [31]
1 year ago
9

Hydrogen and iodine gas react to form hydrogen iodide, as shown in the equation H2(g) + I2(g) → 2HI(g). Suppose you are given a

time interval from t1 = 10 seconds to t2 = 20 seconds and a change in H2 concentration from0.210 mol/L to 0.185 mol/L. Use the reaction rate equation to calculate the average reaction rate during that time period. Show your work.
Chemistry
1 answer:
Leona [35]1 year ago
5 0

The average reaction rate during that time period is 0.0025 mol/l.

<h3>What is concentration?</h3>

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

t_1 = 10 seconds

t_2 = 20 seconds

C_1 = 0.210 mol/L

C_2 = 0.185 mol/L

∆C = |C_2–C_1| = |0.185-0.21| = 0.025 mol/l

∆t = t_2– t_1 = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  \frac{\Delta C}{\Delta t} = \frac {0.025}{10}= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

Learn more about the concentration here:

brainly.com/question/10725862

#SPJ1

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<h2><u>Answer:</u></h2>

0.126 Liters

<h2><u>Explanation:</u></h2>

V = mRT / mmP

First, convert the 2.25g of Nitrogen gas into moles. (m in the equation above)

2.25g x 1 mole / 28.0g = 0.08036 moles = m

28.0g = mm

Next, convert the 273 Celsius into Kelvin. (T in the equation above)

273 Celsius + 273.15 = 546.15K = T

R = 0.08206L*atm/mol*K

(Quick Note: The R changes depending on the Pressure Unit so do not use this number every time.)

Now, plug everything into the equation.

V = (0.08036)(0.08206)(546.15)/(28.0)(1.02)

V = 0.126 L

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A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
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