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Molodets [167]
3 years ago
5

Hydrogen gas can be prepared in the laboratory by a sin- gle-displacement reaction in which solid zinc reacts with hydrochloric

acid. How much zinc in grams is required to make 14.5 g of hydrogen gas through this reaction
Chemistry
1 answer:
vodomira [7]3 years ago
6 0

Answer:

941 g

Explanation:

Step 1: Write the balanced equation

Zn + 2 HCl ⇒ ZnCl₂ + H₂

Step 2: Calculate the moles corresponding to 14.5 g of H₂

The molar mass of H₂ is 1.01 g/mol.

14.5 g × 1 mol/1.01 g = 14.4 mol

Step 3: Calculate the number of moles of Zn required to form 14.4 moles of H₂

The molar ratio of Zn to H₂ is 1:1. The moles of Zn required are 1/1 × 14.4 mol = 14.4 mol.

Step 4: Calculate the mass corresponding to 14.4 moles of Zn

The molar mass of Zn is 65.38 g/mol.

14.4 mol × 65.38 g/mol = 941 g

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Explanation:

Given:

20.5 torr

78.6 torr

225 torr

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Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

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2. 78.6 torr

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3. 225 torr

= 225 x 0.00131579 atm

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<span>he introduced his law of triads. each triad was a group of three elements</span>
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Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

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Volume of the pyramid = V=\frac{1}{3}lwh

We have:

Rate at which water is filled in cube = \frac{dV}{dt}= 45 cm^3/s

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

V=\frac{1}{3}\times l^2\times h

\frac{l}{h}=\frac{6}{13}

l=\frac{6h}{13}

V=\frac{1}{3}\times (\frac{6h}{13})^2\times h

V=\frac{12}{169}h^3

Differentiating V with respect to dt:

\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}

\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}

Putting, h = 4 cm

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}

=13.20 cm/s

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3 years ago
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Explanation:

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Explanation :

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From the balanced chemical reaction, we conclude that

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