Answer:
We can just use the formula for the volume of sphere which is 4/3 PI R cubed R is the radius. So if you have a balloon that's a sphere.
Explanation:
Answer : The pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.
Explanation :
First we have to calculate the pressure of gas by using ideal gas equation.
where,
P = Pressure of 
gas = ?
V = Volume of gas = 0.805 L
n = number of moles = 1.93 mole
R = Gas constant = 
T = Temperature of gas = 306 K
Now put all the given values in above equation, we get:
Now we have to calculate the pressure of gas by using van der Waals equation.
P = Pressure of gas = ?
V = Volume of gas = 0.805 L
n = number of moles = 1.93 mole
R = Gas constant =
T = Temperature of gas = 306 K
a = pressure constant = 
b = volume constant = 
Now put all the given values in above equation, we get:
![(P+\frac{(4.19L^2atm/mol^2)\times (1.93mole)^2}{(0.805L)^2})[0.805L-(1.93mole)\times (5.11\times 10^{-2}L/mol)]=1.93mole\times (0.0821L.atm/mol.K)\times 306K](https://tex.z-dn.net/?f=%28P%2B%5Cfrac%7B%284.19L%5E2atm%2Fmol%5E2%29%5Ctimes%20%281.93mole%29%5E2%7D%7B%280.805L%29%5E2%7D%29%5B0.805L-%281.93mole%29%5Ctimes%20%285.11%5Ctimes%2010%5E%7B-2%7DL%2Fmol%29%5D%3D1.93mole%5Ctimes%20%280.0821L.atm%2Fmol.K%29%5Ctimes%20306K)
Therefore, the pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.
The chain reaction is easy to stop. Just add a neuron absorbing material. The Control Rods in rectors can do that You just SCRAM (put the rods all the way in) or add something like Boron and the chain reaction stops.
<span>The problem is the radioactive waste. Those isotopes break down and release heat spontaneously, no neutrons required. The only known way to stop or slow radioactive decay down is to slow time down by moving at relativistic speed or near orbit to a black hole.</span>
What language is that because I speak English
Answer:
Option e is correct
The heat required to increase the temperature of copper metal by 1 degree is 0.754 j
.
Explanation:
Given data:
specific heat of copper = 0.377 j/g.°C
Heat required to increase temperature = ?
Mass of copper = 2.00 g
Change in temperature = 1°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
Q = 2 g× 0.377 j/g.°C × 1°C
Q = 0.754 j
The heat required to increase the temperature of copper metal by 1 degree is 0.754 j
.
