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3 years ago

15

Some table salt substitutes have potassium chloride in them. If you consume potassium chloride, are you truly eating potassium a

nd chlorine atoms? Support your answer with chemical evidence.

1 answer:

4vir4ik [10]3 years ago

8 0

Answer:

You are consuming both

Explaination

2Na(s)+Cl two(g)

That gives us 2NaCl(s)

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The equilibrium constant for the reaction Ni2+(aq) + 6 NH3(aq) ⇌ Ni(NH3)6 2+(aq) is Kf = 5.6 × 108 at 25°C. (a) What is ΔG o at

shusha [124]

Answer:

(a) -49.9 kJ/mol;

(b) To the right;

(c) 34.6 kJ/mol

Explanation:

(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:

$\Delta G^o = -RT ln (K_f)$

Substituting the given variables:

$\Delta G^o = -8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln (5.6\cdot 10^8) = -49932 J/mol = -49.9 kJ/mol$

(b) Notice that this reaction is spontaneous, since $\Delta G^o < 0$ . This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.

(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:

$Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}$

Now, notice that $Q_f > K_f$ . In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.

Calculate:

$\Delta G = \Delta G^o + RT ln Q_f = -49932 J/mol + 8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln(6.4\cdot 10^{14}) = 34577 J = 34.6 kJ/mol$

5 0

4 years ago

At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of

Dvinal [7]

The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{CO_2}=K_H\times p_{CO_2}$

where,

$K_H$ = Henry's constant = $0.031M/atm$

$C_{CO_2}$ = molar solubility of carbon dioxide gas

$p_{CO_2}$ = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

$C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = $0.0905mol/L$

Volume of solution = 425 mL

Putting values in above equation, we get:

$0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g$

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

8 0

3 years ago

What is the molarity of a solution that has 2.52 grams of NaCO3 dissolved to

sammy [17]

Answer:

Explanation:

2.52g/ 0.125L= 20.16M

5 0

3 years ago

A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.

s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0

3 years ago

The distance between the nuclei of two iron atoms is about 4 angstroms.a. Trueb. False

vladimir2022 [97]

Answer:

The correct option is b. false

Explanation:

The distance between the nucleus of an atom and it's outermost shell is called is atomic radius. The atomic radius of an Iron atom (Fe) is 0.126 nm or 1.26 angstrom. The distance between the nuclei of two Iron atoms will be 1.26 × 2 = 2.52 angstroms.

Since 2.52 angstroms is lower than 4 angstroms, the correct option is false

8 0

3 years ago