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3241004551 [841]
3 years ago
10

Why are city streets so vital to the functioning of a city, as well as the people living within it?

Chemistry
1 answer:
maw [93]3 years ago
7 0
In the city, there is more people there including more resources. They also have a lot of good stuff in the city because they know it will attract a lot of people there because cities are so crowded.
You might be interested in
Which equation represents a transuranium​
Maksim231197 [3]

Answer:

1) Since you have not provided the equations to select the right one, I am going to explain you the relevant facts that are used to solve this question.

2) The transuranium elements are the chemiical elements with atomic number greater than that of the uranium.

The atomic number of uranium is 92. So, the transuranium elements are the elements with atomic number 93 or greater.

This are some of the transuranium elements:

Neptunio - 93

Plutonium - 94

Americium - 95

Curium - 96

Berkelium - 97

Californium - 98

Einstenium - 99

And so all the known elements (the last one is the 118).

3) In a nuclear reaction the total mass number ( shown as superscript to the left of the symbol) and total atomic number (shown as subscript to the left of the symbol) are conserved.

4) Beta decay is the release of a beta particle, which is an electron (considered massles and with charge - 1). So, the beta decay is represented with the symbol:

0

 β, which means 0 mass and charge - 1.

-1

5) This is, then, an example of a β decay equation for one transuranium element:

239              239            0

     Np    →         Pu   +      β

 93                94            -1

As you see 239 = 239 + 0 and 93 = 94 - 1, showing that the total mass number ( shown as superscript to the left of the symbol) and the total atomic number (shown as subscript to the left of the symbol) are conserved.

Explanation:

3 0
3 years ago
A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.
adell [148]

Answer:

a) V=4.3x10^3mL

b) V=4.3x10^6mm^3

c) \rho=1.5x10^5g/L

Explanation:

Hello,

a) In this case, the given height in cm is:

h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm

And the radius in cm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL

b) In this case, the given height in mm is:

h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm

And the radius in mm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm

Thus, the volume in cubic millimeters is:

V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\   \\\rho=1.5x10^5g/L

Best regards.

8 0
3 years ago
If I add 5.0 mL of water to 8.0 mL of a 6.0M NaOH solution, what
erastova [34]

Answer:fdfgfdgfdgfdgfd

Explanation:

3 0
3 years ago
Blank and blank are examples of solids
Ymorist [56]
A box and a laptop are both examples of solids


hope i helped:)
3 0
2 years ago
Does chlorine have a smaller ionic radius than soium.
mafiozo [28]

Answer:

sodium atoms are much larger than chlorine atoms but in case of sodium ions they are much smaller thqn chlorine ions

4 0
2 years ago
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