Answer:
Is that you, Mommy?
Step-by-step explanation:
:)
Answer:
t+3r
Step-by-step explanation:
This is a one step solution
All you do is add like terms
In this case the only like terms are the varibles r
2r+(t+r)
so if you add all of the rs together there would be 3rs
So the rest of the problem would continue as normal while bringing the 3r to the end
t+3r
<span>a mathematical expression or function so related to another that their product is one; the quantity obtained by dividing the number one by a given quantity.
</span>
Answer:
// C++ Program to arithmetic operationf on 2 Numbers using Recursion
// Comments are used for explanatory purpose
#include <bits/stdc++.h>
using namespace std;
// add10 recursive function to perform arithmetic operations
int add10(int m, int n)
{
return (m + product(n, 10)); //Result of m + n * 10
return 0;
}
// Main Methods Starts here
int main()
{
int m, n; // 2 Variables m and n declared as integer
cin>>m; // accept input for m
cin>>n; // accept input for n
cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n
return 0;
}
