Answer:
Explanation:
We shall apply conservation of momentum law in vector form to solve the problem .
Initial momentum = 0
momentum of 12 g piece
= .012 x 37 i since it moves along x axis .
= .444 i
momentum of 22 g
= .022 x 34 j
= .748 j
Let momentum of third piece = p
total momentum
= p + .444 i + .748 j
so
applying conservation law of momentum
p + .444 i + .748 j = 0
p = - .444 i - .748 j
magnitude of p
= √ ( .444² + .748² )
= .87 kg m /s
mass of third piece = 58 - ( 12 + 22 )
= 24 g = .024 kg
if v be its velocity
.024 v = .87
v = 36.25 m / s .
An impulsive force is a force that is acting only during a short time, I mean, for an instant. Impulse is a physics magnitude define by the product of the impulsive force and the time that it was acting.
Is there any mistake in my English? Please, let me know.
Answer:
<h2>23.33 kg </h2>
Explanation:
The mass of the object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>23.33 kg</h3>
Hope this helps you
Answer:
1.11×10⁸ Electrons.
Explanation:
Applying,
Q = CV..................... Equation 1
Where Q = Total charge on the capacitor, C = Capacitance of the capacitor, V = Voltage of the battery.
Given: C = 1.97 pF = 1.97×10⁻¹² F, V = 9.0 V
Substitute this value into equation 1
Q = 1.97×9×10⁻¹²
Q = 1.773×10⁻¹¹ C.
If the charge on one electron = 1.602×10⁻¹⁹ C.
Therefore number of electron = 1.773×10⁻¹¹ /1.602×10⁻¹⁹
Number of electron = 1.11×10⁸
Answer:
Explanation:
For acceleration due to gravity
g = GM / R² ---------------------------- ( 1 )
At height 2R , radius of orbit is 3R .
If speed of satellite be v
m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )
v² = GM / 3R -------------------------------------- ( 2 )
Dividing (1) and (2)
v² / g = R / 3
v² = gR / 3
v = √( gR / 3 )
