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zavuch27 [327]
3 years ago
13

An iron ball and an aluminum ball of mass 100 g each are heated to the same temperature and then cooled to a temperature of 20°

Physics
2 answers:
MrRa [10]3 years ago
7 0

Answer:

The specific heat of aluminum is greater.

Explanation:

It lost the most heat.

zepelin [54]3 years ago
3 0

Answer:

specific heat of aluminium is more than the specific heat of iron

Explanation:

mass of both the balls, m = 100 g

heat lost by iron is 3.6 kJ and the heat lost by aluminium is 7.2 kJ.

The amount of heat required to raise the temperature of substance by 1°C of mass 1 kg is defined as the specific heat of the substance.

Here, the amount of heat required to raise the temperature of aluminium by teh same amount as that of iron and mass remains same, so it means the opecific heat of aluminium is more than the specific heat of iron.

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What are the Rules of magnetism
Keith_Richards [23]

all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

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3 years ago
The spreading of waves behind an aperture is more for long wavelengths and less for short wavelengths.Less for long wavelengths
Allisa [31]

Answer:

Increase in wavelength of incident wave also increases the spread angle or spread of the interference pattern.

Explanation:

Solution:-

- The diffraction occurs when light bends in the same medium. The bending is the result of light waves "squeezing" through small openings or "curving" around sharp edges.

- Moreover, waves diffract best when the size of the diffraction opening (or grting or groove) corresponds to the size of the wavelength. Hence, light diffracts more through small openings than through larger openings.

- The formula for diffraction shows a direct relationship between the angle of diffraction (theta) and wavelength:

                                         d sin (θ) = m λ

Where,

     λ : Wavelength , θ : The spread angle , d : Slit opening or grating

- We can see that the wavelength λ and spread angle θ are related proportionally. So if we increase the wavelength of incident wave we also increase the spread angle or spread of the interference pattern.

5 0
3 years ago
A ball is dropped off a cliff and falls for 24 seconds. How far did the ball fall from the top down
DerKrebs [107]

Answer:

9266 feet

Explanation:

with Earth's gravity and long it fell that's as good as it gets if there was no other factors like wind mass weight but your welcome

4 0
2 years ago
Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two
Pepsi [2]

Answer:197.504 N

Explanation:

Given

Two Charges with magnitude Q experience a  force of 12.344 N

at distance r

and we know Electrostatic force is given

F=\frac{kq_1q_2}{r^2}

F=\frac{kQ\cdot Q}{r^2}

F=\frac{kQ^2}{r^2}

Now the magnitude of charge is 2Q and is at a distance of \frac{r}{2}

F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}

F'=16F

F'=197.504 N

4 0
3 years ago
The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a
likoan [24]

Answer:

14869817.395 m

Explanation:

\theta=22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians

From Rayleigh Criterion

\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

7 0
3 years ago
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