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ANEK [815]
3 years ago
7

This is Formation of the Solar System Lab Report

Physics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

the answer is B it is right

Explanation:

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A SDOF undamped system is set into free vibration with an initial displacement and an initial velocity. The mass of the system i
loris [4]

Answer:

Explanation:

stiffness k = 160

m = 10

angular frequency ω = \sqrt{\frac{k}{m} }

= \sqrt{\frac{160}{10} }

= 4

ω  = 4

Let x = 4 - A sinωt

when t = 0

x = 4 in

when t = 2 s , x = - 4

- 4 = 4 - A sinωt

8  = A sin 4 x 2

8 = A sin8

A = 8 / sin 8

= 8 / .989

= 8.09 in .

x = 4 - A sinωt

dx / dt = - Aω cosωt

v =  - Aω cosωt

for t = 0

v = - Aω

= - 8.09 x 4

= - 32.36 in / s

initial velocity v = - 32.36 in /s

displacement x for t = 4s

x = 4 - 8.09 sin 4 x 4

= 4 - 8.09 sin 16

= 4 - 8.09 x - .2879

= 4 + 2.33

= 6.33  in.

c ) Amplitude of vibration A = 8.09 in .as calculated above .

4 0
3 years ago
A 250 GeV beam of protons is fired over a distance of 1 km. If the initial size of the wave packet is 1 mm, find its final size
Margarita [4]

Answer:

The final size is approximately equal to the initial size due to a very small relative increase of 1.055\times 10^{- 7} in its size

Solution:

As per the question:

The energy of the proton beam, E = 250 GeV =250\times 10^{9}\times 1.6\times 10^{- 19} = 4\times 10^{- 8} J

Distance covered by photon, d = 1 km = 1000 m

Mass of proton, m_{p} = 1.67\times 10^{- 27} kg

The initial size of the wave packet, \Delta t_{o} = 1 mm = 1\times 10^{- 3} m

Now,

This is relativistic in nature

The rest mass energy associated with the proton is given by:

E = m_{p}c^{2}

E = 1.67\times 10^{- 27}\times (3\times 10^{8})^{2} = 1.503\times 10^{- 10} J

This energy of proton is \simeq 250 GeV

Thus the speed of the proton, v\simeq c

Now, the time taken to cover 1 km = 1000 m of the distance:

T = \frac{1000}{v}

T = \frac{1000}{c} = \frac{1000}{3\times 10^{8}} = 3.34\times 10^{- 6} s

Now, in accordance to the dispersion factor;

\frac{\delta t_{o}}{\Delta t_{o}} = \frac{ht_{o}}{2\pi m_{p}\Delta t_{o}^{2}}

\frac{\delta t_{o}}{\Delta t_{o}} = \frac{6.626\times 10^{- 34}\times 3.34\times 10^{- 6}}{2\pi 1.67\times 10^{- 27}\times (10^{- 3})^{2} = 1.055\times 10^{- 7}

Thus the increase in wave packet's width is relatively quite small.

Hence, we can say that:

\Delta t_{o} = \Delta t

where

\Delta t = final width

3 0
3 years ago
800 J of heat is needed to raise the temperature of 2 kg of iron by 1°C. What is the heat capacity of 3.6 kg of iron?​
Dmitry_Shevchenko [17]

Answer: 1440 J/kg/degree Celsius

Explanation:

Heat capacity = thermal energy required / change in heat

6 0
3 years ago
Velocity differs from speed in that velocity indicates a particle's __________ of motion.
masha68 [24]
Velocity differs from speed in that velocity indicates a particle's <span>direction of motion. 

Therefore, your correct answer is: D</span><span>irection

Good luck with your studies, I hope this helps~!</span>
5 0
3 years ago
A traveling wave has displacement given by y(x,t)=(2.0cm)×cos(2πx−4πt), where x is measured in cm and t in s. what is the speed
quester [9]

Answer:

v = 2 cm/s

Explanation:

The equation of the wave is

y(x,t)   =  (2.0cm)*cos(2π*x−4π*t)

Where,

x is measured in cm

t in s

A more general formula for this equation would be

y(x,t)   =  A*cos(k*x−ω*t)

Where,

A = amplitude.

k = the wavenumber

ω = the angular frequency

The velocity of the wave corresponds to

v = ω/k

v = 4π / 2π = 2 cm/s

v = 2 cm/s

8 0
3 years ago
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