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Bingel [31]
3 years ago
7

The seafloor spreading process at ridges produces what kind of faults?

Physics
1 answer:
irga5000 [103]3 years ago
4 0
Active transform faults are between two tectonic<span> structures or faults.</span>
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A right triangle with the base labeled 40 meters and the height labeled 30 meters. The hypotenuse is a dotted arrow labeled R. W
Pepsi [2]

Answer:

The magnitude of the resultant vector R is 50 meters ⇒ 2nd answer

Explanation:

<u><em>The resultant vector</em></u> is the vector sum of two or more vectors

If the two vectors perpendicular to each other, then the magnitude of

the resultant vector is the square root of the sum of their squares

If x and y are two vectors perpendicular to each other, then the

magnitude of its resultant vector R is:

→ R=\sqrt{x^{2}+y^{2}}

Lets solve the problem

A right triangle with the base labeled 40 meters and the height labeled

30 meters

The hypotenuse is a dotted arrow labeled R

→ The base and the height of the right triangle are perpendicular

→ The hypotenuse is the resultant vector of them

Assume that x represents the base of the triangle and y represents the

height of it

By using the rule above

→ x = 40 m , y = 30 m

→ R=\sqrt{x^{2}+y^{2}}

→ R=\sqrt{(40)^{2}+(30)^{2}}

→ R=\sqrt{1600+900}

→ R=\sqrt{2500}=50

<em>The magnitude of the resultant vector R is 50 meters</em>

7 0
3 years ago
Strontium has how many neutrons
Lilit [14]

Answer:

50

Explanation:

7 0
4 years ago
Read 2 more answers
I walk 500 meters due east from my home and then walk 866
mars1129 [50]

The magnitude of the total displacement is 1000 m

Explanation:

Displacement is a vector quantity connecting the initial position and final position of motion of an object.

The magnitude of the displacement is therefore the distance in a straight line between the initial and final position of motion.

The person in the problem has the following motions:

500 meters due east

866 meters due north

The two motions are perpendicular to each other, so they form the sides of a right triangle, of which the hypothenuse corresponds to the magnitude of the total displacement.

Therefore, the magnitude of the displacement can be simply found by using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{500^2+866^2}=1000 m

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

4 0
4 years ago
A diver can change his rotational inertia by drawing his arms andlegs close to his body in the tuck position. After he leaves th
NeX [460]

Answer:

3.14946 rad/s

Explanation:

I_i = Intial moment of inertia

I_f = Final moment of inertia

\omega_i = Initial angular velocity

\omega_f = Final angular velocity = \dfrac{2}{1.33}\times 2\pi\ rad/s

\dfrac{I_f}{I_i}=\dfrac{1}{3}

In this system the angular momentum is conserved

L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s

The angular velocity when the diver left the board is 3.14946 rad/s

3 0
3 years ago
2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind
Alex777 [14]

The resultant speed of the plane  is (3) 226 m/s

Why?

We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}

ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}

Hence, we have that the resultant speed of the plane  is (3) 226 m/s

Have a nice day!

5 0
3 years ago
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