Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At w
2 answers:
Answer:
Ari catches up to Amanda at 19.3 meters
Explanation:
We have given Ari is swimming a 25-meter race.
It is given that after swimming 6 meters she catches up to Amanda in a ratio of 7:3 from the 6-meter mark.
So ,The distance between 6 meters and 25 meters = 25-6 =19 meters
It is given that she catched Amanda in ratio 7:3
So, she catched her at of the distance
So, the distance at which she catched Amanda
Ari catches 13.3 metres from 6 m marks
So the total distance = 13.33+6 =19.33 meters
So Ari catches up to Amanda at a distance of 19.33 meters
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Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water