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oksian1 [2.3K]
2 years ago
11

Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for f

inding the variance are shown below.
What is the first error she made in computing the variance?

Emi failed to find the difference of 89 - 78 correctly.

Emi divided by N - 1 instead of N.

Emi evaluated (46 - 78)^2 as -(32)^2.

Emi forgot to take the square root of -135.6.

Mathematics
1 answer:
Natali [406]2 years ago
7 0

The error she made is Emi evaluated (46-78)² as - (32)² is wrong.

<h3>What is variance?</h3>

Variance is calculated as the average of squared differences of the data observations from the mean.

Given data: 87, 46, 90, 78, and 89.

Here, the first Emi find the difference of 89 - 78 correctly.

Now, Emi division is also correct.

Now, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

(46-78)² = (-32)²

Here she used the negative sign outside.

Hence, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

Learn more about this concept here:

brainly.com/question/9899363

#SPJ1

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