Answer: The required confidence interval would be (2.72,2.89)
Step-by-step explanation:
Since we have given that
Mean = 2.8 pounds
Standard deviation = 0.24 pounds
n = sample size = 16
We need to find the 80% confidence interval for the mean waste.
z=1.341
So, the confidence interval will be
![\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=(2.8\pm 1.341\times \dfrac{0.24}{\sqrt{16}})\\\\=(2.8\pm 1.314\times 0.06)\\\\=(2.8-0.07884,2.8+0.07884)\\\\=(2.72116,2.87884)](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%5Cpm%20z%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C%3D%282.8%5Cpm%201.341%5Ctimes%20%5Cdfrac%7B0.24%7D%7B%5Csqrt%7B16%7D%7D%29%5C%5C%5C%5C%3D%282.8%5Cpm%201.314%5Ctimes%200.06%29%5C%5C%5C%5C%3D%282.8-0.07884%2C2.8%2B0.07884%29%5C%5C%5C%5C%3D%282.72116%2C2.87884%29)
Hence, the required confidence interval would be (2.72,2.89)
Answer:
c + 2g
Step-by-step explanation:
g + g = 2g
c + 2g
Answer and Step-by-step explanation:
Distribute the 1p to the y and -6 and distribute the 2 to the 3y and 6.
10y - 50 + 6y + 12
Now, combine like terms.
16y - 38
#teamtrees #PAW (Plant and Water)