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Paladinen [302]
2 years ago
9

A system of two linear inequalities is graphed as shown, where the solution region is shaded. Complete the sentences below by de

termining whether each point is, or is not. located in the solution region.
The point (-3.2)
The point (-7.5)
The point (2.-5)
The point (-14,6)
Mathematics
1 answer:
andrezito [222]2 years ago
6 0

All the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

<h3>What is a graph?</h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

When we plot all the points on the graph we can see that all the points The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) are located in the solution region.

Therefore all the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

To know more about graphs follow

brainly.com/question/25020119

#SPJ1

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If h(x) = -3x - 10, find h(-3).<br> Answer<br> -1<br> 2.3<br> -19<br> 1<br> ...?
lara31 [8.8K]
The correct answer is:  [A]:  " - 1 " .
__________________________________________________________
Explanation:
__________________________________________________________
Given:  " If h(x) = -3x <span>−</span><span> 10, find h(-3). "

So; we plug in "-3"  for all values of "x" ; to solve for " h(-3)" ; as follows:

       </span>→  h(-3)  =  -3(-3) − 10 = 9 − 10 = - 1 .

The answer is:  " - 1 " . 
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4 0
3 years ago
Which of the following has the largest value?<br> 1/2 0.09 35%
sergejj [24]

Answer:

1/2

Step-by-step explanation:

its j the biggest its not that hard

7 0
3 years ago
I need help I’m not sure
Daniel [21]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad  (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2}  \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)

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KATRIN_1 [288]
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Katyanochek1 [597]
The area of the resulting figure will be given by:
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=32680+3/8 sq. units
=
7 0
3 years ago
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