Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
The parent function is f(x) = x^3 with domain = all real numbers and range = all real numbers.
The given function is f(x) = x^3 - 2 with domain = all real numbers and range = all real numbers.
M4 would be choice b I know this because I put it in the calculator
Answer:
B
Step-by-step explanation:
First calculate BD using sine ratio in Δ BCD and the exact value
sin60° =
, thus
sin60° =
=
=
=
( cross- multiply )
2BD = 12
( divide both sides by 2 )
BD = 6
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Calculate AD using the tangent ratio in Δ ABD and the exact value
tan30° =
, thus
tan30° =
=
=
=
( cross- multiply )
AD = 6
( divide both sides by
)
AD = 6 → B
Answer:
6(2) + 6(1) = 18
Step-by-step explanation: