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Paladinen [302]
2 years ago
9

A system of two linear inequalities is graphed as shown, where the solution region is shaded. Complete the sentences below by de

termining whether each point is, or is not. located in the solution region.
The point (-3.2)
The point (-7.5)
The point (2.-5)
The point (-14,6)
Mathematics
1 answer:
andrezito [222]2 years ago
6 0

All the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

<h3>What is a graph?</h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

When we plot all the points on the graph we can see that all the points The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) are located in the solution region.

Therefore all the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

To know more about graphs follow

brainly.com/question/25020119

#SPJ1

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3 0
3 years ago
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

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BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

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3 years ago
-7x - 2y = 14<br><br> 6x + 6y = 18<br><br> x =<br><br> y =
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Answer:

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Step-by-step explanation:

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